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Semenov [28]
3 years ago
14

Express ( x + 4 )∧2 as a trinomial in standard form.

Mathematics
2 answers:
mamaluj [8]3 years ago
8 0

Answer: x²+8x+16

Step-by-step explanation:

(x+4)^2=(x+4)(x+4)

Now use distributive property to expand (x+4)(x+4):

(x+4)(x+4)=x²+4x+4x+4(4)

x²+4x+4x+4(4)=x²+8x+16

otez555 [7]3 years ago
5 0

Answer:

x^2+8x+16

Step-by-step explanation:

Assuming that is to the power of two

We can use special products to do this which states that the answer to this will be a^2+2ab+b^2 where the first value is a and the second value is b. So we just plug that in and do x^2+8x+16.

We can also just do (x+4)(x+4) and do that out but that takes more time and you'll get the same answer.

Let me know if you have any questions

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The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si
OverLord2011 [107]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

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Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

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The probability of exactly k arrivals in a particular hour can be written as:

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b) The probability that <em>at least</em> 3 people arrive during a particular hour is:

P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938

c) In this case, t=0.25, so we recalculate the parameter as:

\lambda =r\cdot t=6\;h^{-1}\cdot 0.25 h=1.5

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

E(x)=\lambda=1.5

3 0
3 years ago
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marishachu [46]

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Hope this helps!

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