Question

Hi help me plsss :(((

Answer 1

Answer:

The square root of 121 is 11, the square root of x^2 is x, the square root of y^3 is y and sqrt y, the square root of z^4, is z^2:

11xyz^2 sqrt(y)

Your answer is C

Note: If something is inside a radical, it is raised to an exponent of 1/2. You can rewrite anything inside the radical as raised to 1/2.

Answer 2

Answer:

The choice 3.

$11xy {z}^{2} \sqrt{y}$

Step-by-step explanation:

$\sqrt{121 {x}^{2} {y}^{3} {z}^{4} } = \sqrt{ {11}^{2} {x}^{2} {y}^{2}y ({z}^{2}) ^{2} } \\ \\ = 11xy {z}^{2} \sqrt{y}$