Answer:
(a) OPTION E=4
b) option E C sp² + C p
Explanation:
DEGREE OF UNSATURATION = C -H/2 -X/2 +N/2 +1
X IS HALOGENS
5-5/2+1/2+1= 4
b) Ethene comprises of two sp2-hybridized carbon atoms (bound to each other by sigma and two atoms each with hydrogen). The remaining unhybridized carbon p orbitals form a pi bond, giving ethene reactivity
Answer:
2.00 × 10⁻³ g
Explanation:
Step 1: Write the balanced decomposition reaction
2 NaHCO₃ ⇒ Na₂CO₃ + CO₂ + H₂O
Step 2: Calculate the moles corresponding to 0.0118 g of Na₂CO₃
The molar mass of Na₂CO₃ is 105.99 g/mol.
0.0118 g × 1 mol/105.99 g = 1.11 × 10⁻⁴ mol
Step 3: Calculate the moles of H₂O produced with 1.11 × 10⁻⁴ moles of Na₂CO₃
The molar ratio of Na₂CO₃ to H₂O is 1:1. The moles of H₂O produced are 1/1 × 1.11 × 10⁻⁴ mol = 1.11 × 10⁻⁴ mol.
Step 4: Calculate the mass corresponding to 1.11 × 10⁻⁴ moles of H₂O
The molar mass of H₂O is 18.02 g/mol.
1.11 × 10⁻⁴ mol × 18.02 g/mol = 2.00 × 10⁻³ g
Answer:
Which ever item has more water inside of it
Explanation:
Answer: a. 6(3x2=6)
B. 4(4x1=4)
C. 6(4(1)+2(1)=4+2=6
D. 4
E. 6(3(2)=6)
F. 4(2(1)+2(1)[2+2=4)
G. 5(5(1)=5)
H. 4(2(1)+2(1)=2+2=4)
Explanation:
Coordination number= no of ligands
= No of ligands X denticity
Denticity is nothing but type of ligands like mono,do and tetradentate ligands.
Hydrogen is the smallest elements , with one potron and one electron .it is highly abundant no has unique and important chemicals properties .