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Answer: Hello your question is incomplete below is the complete question
In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport. in the same district, 19 of 67 randomly selected high school juniors play a varsity sport. a 95 percent confidence interval for the difference between the proportion of high school seniors who play a varsity sport in the school district and high school juniors who play a varsity sport in the school district is to be calculated. What is the standard error of the difference
answer : 0.0695
Step-by-step explanation:
First step : Determine the sample proportions
For P1 = 16 / 85 = 0.188
For P2 = 19 / 67 = 0.284
Next determine the Standard error of the difference using the relation below
Standard Error = ------- ( 1 )
where : P1 = 0.188
P2 = 0.284
n1 = 85 high school seniors
n2 = 67 high school juniors
Input values into equation 1
Standard error of the difference = 0.0695