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vova2212 [387]
2 years ago
14

1 4/8 in a improper fraction?

Mathematics
1 answer:
stiv31 [10]2 years ago
8 0
<h2>Answer:\frac{3}{2}<u><em></em></u></h2>

Step-by-step explanation:

Step 1: Multiply the whole number part (1) by the denominator (8).

1 × 8 = 8

Step 2: Add the product from Step 1 (8) to the numerator (4).

8 + 4 = 12

Step 3: Write that result (12) above the denominator. So,

\frac4{8}{1}

Step 4: The fraction \frac{12}{8}

Can be reduced by dividing both numerator and denominator by the GCD(12,8) = 4. Thus,

\frac1{4}{8} =\frac{3}{2}

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Two freind whant to share 3 apples so that they have the same amount \
IRINA_888 [86]
Each of the friends would have 1.5 apples since 3 divided by 2 is 1.5
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3 years ago
Which number from the set {0,2,3,4} makes this inequality true?
sdas [7]

Answer:

C

Step-by-step explanation:

6x - 10 > 2x + 2

4x - 10 > 2

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7 0
2 years ago
What 3 numbers multiply to get 63?
masya89 [10]
There are many combinations if the numbers are not required to be integers.

If they are required to be integers, I'd suggest:

3*7*3 = 63
5 0
3 years ago
Read 2 more answers
Which of the following equations is equivalent to 3(2p + 4) - (3p - 4) = 43?
emmainna [20.7K]
Answer: (use distributive property then add the like terms)
3(2p + 4) - (3p - 4) = 43
6p + 12 - 3p - 4 = 43
3p - 8 = 43
6 0
2 years ago
On the first part of her trip Natalie rode her bike 16 miles and on the second part of the trip she rode her bike 42 miles. Her
-BARSIC- [3]

Answer:

14 mph   ( average speed during the second part of the trip )

Step-by-step explanation:

Let´s call  "x"  the average speed during the first part then

t = 5 hours

t  =  t₁  +  t₂        t₁   and  t₂   times during part 1 and 2 respectively

l = t*v           (  distance is speed by time )      t =  l/v

First part

t₁  = 16/x        and      t₂  = 42 / ( x + 6)

Then

t =   5   =  16/x   +   42 /(x + 6)

5 = [ 16 * ( x  +  6 ) +  42 * x ] / x* ( x + 6 )

5 *x * ( x + 6 )  =  16*x  + 96 +  42 x

5*x² + 30*x  - 58*x - 96  =  0

5*x²  -  28*x  -  96  =  0

We obtained a second degree equation, we will solve for x and dismiss any negative root since negative time has not sense

x₁,₂  =   [28 ± √ (28)² + 1920  ] / 10

x₁,₂  = ( 28  ± √2704 )/ 10

x₁  = 28  -  52 /10        we dismiss that root

x₂  = 80/10

x₂  =  8 mph       average speed during the first part, and the average speed in the second part was 6 more miles than in the firsst part. then the average spedd dring the scond part was 8 + 6 = 14 mph

6 0
3 years ago
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