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MakcuM [25]
3 years ago
12

You are asked to separate sand and sodium chloride.

Chemistry
2 answers:
mash [69]3 years ago
8 0
One can dissolve the mixture of sodium chloride and sand in water, because sand doesn’t dissolve but sodium chloride does.
Igoryamba3 years ago
5 0

Answer:

Explanation:nono

noooooooooooooooooooooooooooooooooooooo

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A solution is prepared by dissolving 8.75 grams of sodium chloride in enough volume of water to produce 112.0 grams of the NaCl
ICE Princess25 [194]

Answer : The percent by mass of the solution is 7.81 %

Explanation : Given,

Mass of NaCl = 8.75 g

Mass of solution = 112.0 g

Now we have to determine the percent by mass of the solution.

\text{Mass percent}=\frac{\text{Mass of NaCl}}{\text{Mass of solution}}\times 100

Putting values in above equation, we get:

\text{Mass percent}=\frac{8.75g}{112.0g}\times 100=7.81\%

Therefore, the percent by mass of the solution is 7.81 %

6 0
3 years ago
Stuck on question 22
Klio2033 [76]
The answer is c. because you have to increase concentration of h2
7 0
4 years ago
If 22.5L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at constant temperature. What is the new volume?2.A gas with a vol
kykrilka [37]

Answer:

a)23.2 L

b)68.3kPa

c)7.5 atm

d)60.5L

e)1.67 atm

Explanation:

From Boyle's law:

P1V1=P2V2

P1= 748mmHg

P2=725mmHg

V1= 22.5L

V2??

V2= P1V1/P2= 748×22.5/725= 23.2 L

b)

V1=4.0L

P1= 205×10^3Pa

V2= 12.0L

P2=???

P2= P1V1/V2= 205×10^3×4/12

P2= 68.3×10^3 Pa or 68.3kPa

c)

P1= 1 atm

V1= 196.0L

P2= ??

V2= 26.0L

P2= P1V1/V2=1×196.0/26.0

P2= 7.5 atm

d)

V1= 40.0L

P1= 12.7×10^3Pa

V2=???

P2= 8.4×103Pa

V2= P1V1/P2= 12.7×10^3×40.0/8.4×103

V2=60.5L

e)

V1= 100mL

P1= 1atm

V2= 60mL

P2=???

P2= P1V1/V2= 1×100/60

P2= 1.67 atm

4 0
4 years ago
Can you check this for me?
Aliun [14]
Hi, your answer is correct.
3 0
4 years ago
In which process are glucose and oxygen the reactants?
Alenkasestr [34]
The answer is B. Cellular Respiration, for sure.
7 0
4 years ago
Read 2 more answers
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