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Scrat [10]
3 years ago
13

Which weak acid solution has the greatest percent ionization? which weak acid solution has the greatest percent ionization? 0.14

0 m h2c6h6o6 0.700 m h2c6h6o6 0.0140 m h2c6h6o6?
Chemistry
1 answer:
sweet [91]3 years ago
5 0

Answer:

0.0140 M H₂C₆H₆O₆.

Explanation:

  • We should mention the relation: <em>Ka = α²C,</em>

Where, Ka is the dissociation constant of the acid.

α is the degree of ionization of the acid.

C is the concentration if the acid.

<em>The percent of ionization (α %) = α x 100.</em>

α = √Ka/C

∴ α is inversely proportional to the concentration of the acid.

<em>So, the acid with the lowest concentration has the greatest percent ionization.</em>

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Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres
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<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (KCl) = 5.0 g

M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

3 0
2 years ago
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Answer:

It's Effective Collision.

Explanation:

Hope my answer has helped you!

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8.3

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When 25.0 grams of solid potassium hydroxide (KOH, molar mass = 56.1 g/mol) is dissolved in 100.0 grams of water, the solution i
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Answer:

They gave you the equation; Cp=,

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