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butalik [34]
3 years ago
9

Lol nevermindnevermindnevermindnevermind

Chemistry
2 answers:
Ivenika [448]3 years ago
8 0

Answer:

never what?

Explanation:

you sure you good

BigorU [14]3 years ago
5 0
Alright thennnnnnnnnn
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What is the total number of hydrogen atoms contained in one molecule of (NH4)2C204?
Ber [7]

Answer:

=8 atoms

Explanation:

In (NH4)2C2O4 there are four moles of Hydrogen in the compound (NH4), but there two molecules of (NH4) in this compound.  That's what the 2 in (NH4)2 means, so multiply 4 x 2 = 8.

Hope this helps (:

8 0
3 years ago
Read 2 more answers
What is the number of moles of glucose C6H12O6 in a 134g sample?
Shkiper50 [21]
The question is simply asking to convert from units of mass to units of moles. To do this, a conversion factor is needed. For this case, we use the molar mass of glucose which is equal to 180.18 g/mol. We do as follows:

134 g C6H12O6 ( 1 mol / 180.18 g ) = 0.744 mol <span>C6H12O6</span>
5 0
4 years ago
The free energy of formation of nitric oxide, NO, at 1000 K (roughly the temperature in an automobile engine during ignition) is
Assoli18 [71]

<u>Answer:</u> The value of K_p for the chemical equation is 8.341\times 10^{-5}

<u>Explanation:</u>

For the given chemical equation:

N_2(g)+O_2(g)\rightarrow 2NO(g)

To calculate the K_p for given value of Gibbs free energy, we use the relation:

\Delta G=-RT\ln K_p

where,

\Delta G = Gibbs free energy = 78 kJ/mol = 78000 J/mol  (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

T = temperature = 1000 K

K_p = equilibrium constant in terms of partial pressure = ?

Putting values in above equation, we get:

78000J/mol=-(8.314J/Kmol)\times 1000K\times \ln K_p\\\\Kp=8.341\times 10^{-5}

Hence, the value of K_p for the chemical equation is 8.341\times 10^{-5}

4 0
4 years ago
What volume of 0.75M KCl is needed to make 40.0mL of 0.500M solution? (10 Points)​
AlexFokin [52]

Answer:

100mg

Explanation:

5 0
3 years ago
Which 2 not one 2! hjmdnxhjund
mariarad [96]

Answer:

A and D then I guess

Explanation:

sorry hope this helps!

7 0
3 years ago
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