First, determine the number of computers that are needed for 924 students.
n = (924 students)(5 computers / 12 students)
n = 385 computers
Since, there are only 125 computers, the difference can be calculated.
d = 385 computers - 125 computers
d = 260 computers
Hence, 260 more computers are still needed.
According to CollegeBoard.org:
<u>Answer</u>: "To estimate the probability of observing a value as extreme as pˆ given p."
<u>Explanation</u>: "The test statistic for a one-sample z-test is the distance, in units of standard deviations, between the statistic and the given parameter. From that distance, probabilities (a p-value) can be calculated and a claim can be assessed."
Slope = 3.1
This is in y =mx + b
Where m = slope
The lcm of 6 and 18 is C.)18
