let's bear in mind that
standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
so, let's do away with the denominators by multiplying both sides by the LCD of all fractions, in this case 6.
Actually Welcome to the Concept of the Quadrilaterals.
Basically we know that, the sum of opposite angles of a quadrilateral inscribed in a circle is always 180°.
so applying this law here, we get as,
2X + (3X-10) = 180°
=> 5X - 10° = 180°
=> 5X = 190°
=> X = 190°/5
=> X = 38°
thus the angle X= 38°.
Step-by-step explanation:
The slope of tghe line (m) = (y₂ - y₁) ÷ (x₂ - x₁)
= (- 6 -0) ÷ ( 0 - 7)
= ⁶/₇
We can now use the point-slope form to write the equation for this line:
y - y₁ = m(x - x₁) where (x₁ , y₁) = (7 , 0)
y = ⁶/₇ ( x - 7 )
