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julia-pushkina [17]
3 years ago
12

The excessive demand of energy leads to......​

Chemistry
1 answer:
dem82 [27]3 years ago
3 0

Answer:

industrial activity

Explanation:

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The number 1x10^100 is called a googol. Write the number 50 googols in standard form.​
lyudmila [28]

Answer:

Explanation:

50 * 10^100 is 50 googols in scientific notation... but

come on, who would write that in standard form...

5 0
3 years ago
Explain why an atom may go through nuclear decay but another won't? use examples to support your answer.
Marta_Voda [28]
Nuclear decay or radioactive decay is a process by which the nucleus of an unstable atom loses energy that is in terms of its mass. The radioactivity may cause an atom to lose whichever of its subatomic particles.

The explanation as why some of the atoms go through nuclear decay while others do not its because of the stability of some atoms. Atoms usually tend to follow octet rule, those which do not follow through this may experience the nuclear decay. 
3 0
4 years ago
How many kJ of heat are required to melt 50.0 g of ice at its melting pt?
Norma-Jean [14]
You need the heat of fusion of ice to solve this problem. <span>the heat of fusion of water = 334 J/g </span><span>

the formula to solve for heat is </span>q = m·ΔH<span>f</span>

just plug the values

q= (50.0 g) (334 j/g)= 16700 joules or 16.7 Kj
5 0
3 years ago
HELP ITS URGENT!! ( photo included)
shtirl [24]

Answer:

first one is a second is c

Explanation:

6 0
4 years ago
A compound is 53.31 % C , 11.18 % H , and 35.51 % O by mass. What is its empirical formula? Insert subscripts as needed.
Amanda [17]

Answer:

The empirical formula is C2H5O

Explanation:

Step 1: Data given

Suppose the mass of the compound = 100.0 grams

The compound contains:

53.31 % C = 53.31 grams C

11.18 % H = 11.18 grams H

35.51 % O = 35.51 grams O

Step 2: Calculate moles

moles = mass / molar mass

Moles C = 53.31 grams / 12.01 g/mol

Moles C = 4.439 moles

Moles H = 11.18 grams / 1.01 g/mol

Moles H = 11.07 moles

Moles O = 35.51 grams / 16.0 g/mol

Moles O = 2.22 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

C: 4.439 / 2.22 = 2

H: 11.07 / 2.22 = 5

O: 2.22/2.22 = 1

C2H5O

The empirical formula is C2H5O

5 0
3 years ago
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