Answer:
4x^3-16x^2-28x+40
It will take a while to describe how i got this, but i checked the zeroes are ok.
Answer:
Tn=a + (n-1)d
a= first term = 14
n= This is the term you're looking for... In this case... That's the 73rd term
d=Common difference (since its an AP)
d= second term - first term -- Or 3rd term - 2nd term = 23-14
d=9
T = 14 + (73-1)9
T= 14 + (72)9
T= 14 + 648
T=662.
Answer:
Find how much she will be paid per mile to make it easier.
.25 * 4 = 1
.90 * 4 = 3.60
Now you know she earns 3.60 per mile, multiply that by 7.
3.60 * 7 = $25.20 total.
Hello here is a solution :
<span>x² − 8x − 4 = 0.
</span><span>quadratic equation ax²+bx+c = 0 when : a=1 and b= -8 and c = -4
discriminant : d = b²-4ac d= (-8)²-4(1)(-4) =64+16 =70
x= (-b-rot(d))/2a </span>x'= (-b+rot(d))/2a .......conrinu