The answer is 3. To find the interquartile range, all you have to do is subtract your Q3-Q1. In this case, all you do is
20-17=3
Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
The correct answer is the 5th option (one before the last one).
Answer:
5 of the 7 boxes are 8 inches in height
Step-by-step explanation:
Mathematically;
1 ft = 12 inches
So, 5 ft will measure 5 * 12 = 60 inches
So from what we have ,
We want to combine 8 and 10 inches to give 60 inches total
Let the number of 10 inches be x and the number of 8 inches be y
Mathematically;
x + y = 7 •••••(i)
10x + 8y = 60 ••••(ii)
From equation i, x = 7-y
Put this in equation ii
10(7-y) + 8y = 60
70-10y + 8y = 60
70-60 = 10y-8y
2y = 10
y = 10/2
y = 5
A = ( 15 , 15 )
B = ( 6 , 33 )
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