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Ad libitum [116K]
2 years ago
8

Simplify 5) 7+8.3(-7.7t + 4n) + 5.6n - t +3.8

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
7 0
Answer: 10.8-62.91t+38.8n
Step-by-step explanation:
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Simplify (92 – 3 × 7) ÷ (7 – 3)
Illusion [34]

Answer:

17 3/4

Step-by-step explanation:

Equation: (92 - 3*7)/(7-3)

PEMDAS so parenthesis first. Then multiplication so 7 times 3 is 21. For 7 minus 3 would be four. Like this: (92-21)/4

Subtraction: 71/4

Answer: 17 3/4

8 0
3 years ago
Read 2 more answers
Find the unit price
Mrac [35]

Answer:

Price per ounce is $0.062

Step-by-step explanation:

Here, we want to find the unit price in which this vase is price per ounce

Firstly, we need the total ounce value

1 pound = 16 ounce

so two pounds will be 2 * 16 = 32 ounces

So the total ounce value is 32 ounces + 8 ounce = 40 ounces

So 40 ounces = $2.48

price per ounce will be $2.48/40 = $0.062 per ounce

3 0
3 years ago
Please help it's due tmrw
Makovka662 [10]

Answer:

B

If you just use you finger to keep track of one point and follow each set of instructions you will find that B is correct.

I realize that in a previous comment I had said im bad at geometry but I immediately assumed this had to do with ASA and such.

5 0
3 years ago
A collection of nickels and quarters is worth 2.85 . There are 3 more nickels than quarters how many nickels and quarters are th
Zolol [24]

A nickel is equal to 5 cents or 0.05 dollars.

A quarter is equal to 25 cents or 0.25 dollars.

Let number of nickels be = n

Let number of quarters be = q

0.05n+0.25q=2.85    ...........(1)

As it is given, there are 3 more nickels than quarters so equation becomes,

n=q+3   ................(2)

Plug in the value of 'n' from (2) in (1)

0.05(q+3)+0.25q=2.85

= 0.05q+0.15+0.25q=2.85

0.30q=2.70

q=9

As n=q+3 we get, n=9+3=12

Hence, there are 12 nickels and 9 quarters.

3 0
3 years ago
Let f ( ) sin(arctan ) x x = . What is the range of f ?
nikklg [1K]
<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>

And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
5 0
3 years ago
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