The first two ionization energy of nickel are expressed as:
Ni(g) = Ni^+(g) + e^- Ni^+(g) = Ni^2+(g) + e^-
IOnization energy os the energy that is neccessary in order to remove one mole of electrons from an atom.
Hope this helps.
Answer:
Strong attraction between ions and the second one High melting points
Explanation:
Answer:
The ribosome contains three grooves which are sites for the tRNA. The first codon is AUG, which is called a "start codon". ... So, the tRNA that has the anti-codon sequence of UAC carrying the amino acid Met bonds to the mRNA codon. Another tRNA bonds to the next codon in the next groove with the next amino acid
Can you ask your question more thoroughly?
<u>Answer:</u> The equilibrium constant for the given reaction is 0.8
<u>Explanation:</u>
Equilibrium constant is defined as the ratio of concentration of the products raised to the power its stoichiometric coefficients to the concentration of reactants raised to power its stoichiometric coefficient. It is represented as 
For the general equation:

The equilibrium constant is represented as:
![K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
For the given chemical equation:

for this equation is given by:
![K_c=\frac{[H_2O][CO]}{[H_2][CO_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2O%5D%5BCO%5D%7D%7B%5BH_2%5D%5BCO_2%5D%7D)
Concentration at equilibrium of

Putting values in above equation, we get:

Hence, the equilibrium constant for the given chemical reaction is 0.8