All categories

3 years ago

Cze-koip-vmu ao ladkiyo

Mathematics

1 answer:

malfutka [58]3 years ago

8 0

Answer:

cze-koip-vmu ao ladkiyo

You might be interested in

My other account just got banned for 40 something hour's how lame and I did nun so idk why I got banned but it's whatever

Alexxx [7]

Answer:

it is what is iss

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Can someone help me with these? Pls Answer ill mark Brainliest

Nat2105 [25]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

for A class trip, 144 students are put on 4 buses .At this rate how many students would be on 8 buses. Plz put work

dedylja [7]

Answer: 288 students

Step-by-step explanation:

First Step: find the number of students per bus

Given

- 144 students

- 4 bus

Solve

144 students/4 buses=36 students/bus

Second Step: apply the rate to find the number of students in 8 buses

Given

- 8 buses

- 36 students/bus

Solve

8×36=288 students

Hope this helps!! :)

Please let me know if you have any questions

3 0

3 years ago

The amount that Jimmy paid for his meals the four days, $6.45, $21.38, $1.99, $7.99, $16, $0, $7.99, $18.95, $4.30, $10.35, $18.

ella [17]

Answer:

$7.99

Step-by-step explanation:

Arrange numbers in numerical order: $0, $1.99, $4.30, $6.45, $7.99, $7.99, $10.35, $16, $18.20, $18.95, $21.38.

Count how many numbers you have, 11.

11 is an odd number so, the number in the middle of the data set is the median.

Final answer: $7.99 is the median.

7 0

3 years ago

Without actual division prove that x4 +2x3 -2x2 +2x -3 is exactly divisible by x2 +2x-3

Brut [27]

Answer:

Step-by-step explanation:

$\displaystyle\Large\boldsymbol{} x^4+2x^3-2x^2+2x-3= \\\\\\x^4+2x^2(x-1)+2x-\underbrace{2-1}_{-3}= \\\\\\x^4-1+2x^2(x-1)+2x-2 = \\\\\\(x^2-1)(x^2+1)+2x^2(x-1)+2(x-1) = \\\\\\\underline{(x-1)}(x+1)(x^2+1)+2x^2\underline{(x-1)} +2\underline{(x-1)} =\\\\\\(x-1)((x+1)(x^2+1)+2x^2+2)=\\\\\\(x-1)(x^3+x^2+2x^2+x+2+1)=\\\\\\(x-1)(x^3+3x^2+x+3) =\\\\\\(x-1)( \underline{(x+3)}x^2+\underline{(x+3)})=(x^2+1)\underbrace{(x-1)(x+3)}_{x^2+2x-3}= \\\\\\(x^2+1)(x^2+2x-3) : (x^2+2x-3)=x^2+1$

7 0

3 years ago