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3 years ago

Given that f(x)=2x+3 , find: f(5x+3)

Mathematics

1 answer:

PIT_PIT [208]3 years ago

5 0

Answer:

f(5x+3) = 10x + 9

Step-by-step explanation:

f(x) = 2x + 3

f(5x+3) = ??

Given this information, we know that x = 5x + 3. Therefore, to solve the new equation we need to plug 5x + 3 into the original equation

f(5x+3) = 2(5x+3) + 3

Now we distribute the 2

f(5x+3) = 10x + 6 + 3

Finally, combine like terms

f(5x+3) = 10x + 9

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Write an algebrale expression for the phrase "elghe more than three times a<br> number

gavmur [86]

x 3

Step-by-step explanation:

5 0

3 years ago

Which of the following are NOT the lengths of the sides of a triangle?

Evgesh-ka [11]

2,3,6 because 2 and 3 cant equal 6

7 0

3 years ago

the square root of 4,356 is an integer. without a calculator , determine what the integer is by eliminating possibilities.

Zanzabum

It's more than 3600, so its greater than 60.
it's less than 4900, so its less than 70.
a no.'s root can end with six if the no. ends with 4 or 6.
so the no is either 64 or 66.
Now if it's 66, the square must be greater than sq of 65.
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Therefore the number is 66.

5 0

3 years ago

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is . The US

alexandr1967 [171]

Answer:

The answer is "23, 62, and 139"

Step-by-step explanation:

In point a:

$\to \sigma = \$0.24\\\\ \to E = \$0.10\\\\ 95\% \text{confidence level of the z}: \\\\\to \alpha = 1 - 95\% = 1 - 0.95 = 0.05\\\\\to \frac{\alpha}{2} = \frac{0.05}{2} = 0.025\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\$

Calculating the sample size:

$\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma)}{E})^2$

$= (\frac{(1.96 \times 0.24 )}{0.10})^2\\\\= 22.13 \approx 23$

In point b:

$\to \sigma = \$0.24\\\\\to E = \$0.06\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\$

$= (\frac{(1.96 \times 0.24 )}{0.06})^2\\\\= 61.47 \approx 62$

In point c:

$\to \sigma = \$0.24\\\\\to E =\$0.04\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\$

$= (\frac{(1.96\times 0.24 )}{0.04})^2 \\\\=138.30 \approx 139$

4 0

3 years ago

A 40 of foxes in a wildlife preserve quadruples in size every 13 years. The function y=40•4^4, where x is the number of 13-year

SashulF [63]

Answer:

640 foxes

Step-by-step explanation:

The actual formula is $y = 40 * 4^{x}$

Now that we have the real formula we would need to find out how many 13 year periods exist in the 26 years that are being used in the question. We calculate this by simply dividing 26 by 13.

26 / 13 = 2 periods

Therefore, now that we know there are 2 periods of 13 years in the 26-year span, we plug this value into the formula and solve for y...

$y = 40 * 4^{x}$

$y = 40 * 4^{2}$

$y = 40 * 16$

$y = 640$

Finally, we can see that there should be 640 foxes after 26 years.

7 0

3 years ago