16a³b = 8ab(2a²)
24ab² = 8ab(3b)
Lowest Common Multiple = (8ab)(2a²)(3b) = 48a³b²
6a³b x 3b = 48a³b²
24ab² x 2a² = 48a³b²
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Answer: LCM = 48a³b²
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6x 34 because you have to divide and then multi
Answer:
False
Step-by-step explanation:
the domain is the set of numbers you can plug in, and the range is what comes out
4 is shown in both ovals, but we see that there is no arrow pointing from the left oval to the 4 in the right oval, meaning that no value in interval [1,5] has a value of 4.
Answer:
0
Step-by-step explanation:
