Let antonio's age = a and let sarah's age = s
2a + 3s = 34 (given in question)
s = 5a (given in question)
Because we know that s = 5a, we can replace it with 5a in the first equation to give this:
2a + 3(5a) = 34
∴ 2a + 15a = 34
∴ 17a = 34
∴ a = 2
Therefore we can see that Antonio is 2. Because we have been told that Sarah is 5 times Antonio's age, we can say that Sarah is 10.
Answer:
Step-by-step explanation:
<u>-x + 4 equals </u><u>0</u><u>.</u>
<u />
<u>Substitute 4 for x:</u>
<u />
<u>Simplify:</u>
<u />
Answer:
131 minutes, an = 15 + (n - 1)(4)
Step-by-step explanation:
each time she is increasing by 4 minutes
we can write this equation like this since we have the difference and the first part:
an = 15 + (n - 1)(4)
note
"an" (or ace of n)'s n is in subscript and is written just like a superscript but on the bottom
we can plug in this equation to find ace of 30 (a30)
15 + (30 - 1)(4)
15 + 29*4
116 + 15
a30 = 131
<span>5z^2 + 6a
This is because there is an imaginary 1 in front of the second term that you have to remember to use when combining like terms. </span>
