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2 years ago

X=−6.58578643, −9.41421356 what is the rounded decimal of these two?

Mathematics

1 answer:

valentina_108 [34]2 years ago

7 0

Answer:

Depends on which place you're rounding to:

Step-by-step explanation:

Rounded to the tenths place (one number after the decimal point):

x = -6.6, -9.4

Rounded to the hundredths place (two numbers after the decimal place):

x = -6.59, -9.41

Rounded to the thousandths place (three numbers after the decimal place):

x = -6.586, -9.414

I don't think you'd need to round to the ten-thousandths place. If you do lemme know and I'll edit my answer. But you should know if the next digit is 5 or greater like in 15 you'd round up. If it's less than 5, you round down.

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In a certain region, there is a 0.1 probability that any checked passerine bird's nest will

mamaluj [8]

Answer:

Probability of at least two cuckoo eggs is 0.738.

Step-by-step explanation:

probability of cuckoo egg = 0.1

probability of not a cuckoo egg = 1 - 0.1 = 0.9

Probability of at least two cuckoo eggs is

= Probability of two cuckoo eggs x probability of 1 not cuckoo egg +

probability of three cuckoo eggs

= 0.1 x 0.1 x 0.9 + 0.9 x 0.9 x 0.9

= 0.009 + 0.729

= 0.738

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2 years ago

Zander was given two functions: the one represented by the graph and the function f(x) = (x + 4)2. What can he conclude about th

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Answer:

On E2020 the answer is C

Step-by-step explanation:

They have the same y-intercept.

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2 years ago

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Find the equation of the circle with center at (-1, 3) and radius of 4.

Nataly [62]

Answer:

(x+1)^2 + (y-3)^2 = 16

Step-by-step explanation:

The equation of a circle is given by

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

(x--1)^2 + (y-3)^2 = 4^2

(x+1)^2 + (y-3)^2 = 4^2

(x+1)^2 + (y-3)^2 = 16

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2 years ago

Using the information in the table, how many feet are in 6 yards?

Goryan [66]

Answer:

Step-by-step explanation:

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2 years ago

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find a function whose second derivative is y''=12x-2 at each point (x,y) on its graph and y=-x+5 is tangent to the graph at the

pogonyaev

Start by integrating y'' twice to get function y(x).

$y' = \int (12x - 2) dx = 6x^2 -2x + c \\ \\ y = \int (6x^2 -2x+c )dx= 2x^3-x^2 +cx+d$

Next find value of coefficients 'c' and 'd' using the given tangent line
The slope of tangent line is equal to y' when x=1.

$6x^2 -2x+c = -1, x = 1 \\ \\ 6-2+c = -1 \\ \\ c = -5$

The tangent line intersects the curve y(x) when x = 1.
If x = 1, then y = 4 (From y =-x+5)

$y = 2x^3 -x^2-5x +d , x = 1, y = 4 \\ \\ 2-1-5+d = 4 \\ \\ d = 8$

Final Answer:
$y = 2x^3 -x^2 -5x+8$

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2 years ago