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DochEvi [55]
3 years ago
9

Round 290951.867863 to the nearest hundred.

Mathematics
1 answer:
andreev551 [17]3 years ago
5 0

Answer: 290951.87

Step-by-step explanation:

Hope this helps :D

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A certain number added to its square is 30. Find the number
Alex Ar [27]
X+x²=30
x²+x-30=0
(x+6)(x-5)=0
x=-6 or x=5
5 0
3 years ago
PLEASE HELP ITS AN EMERGENCYYYYYYYYYY!!!
lorasvet [3.4K]

Answer:

The value of k is 1.

Step-by-step explanation:

x – 1 is a factor of f(x)

This means that:

x - 1 = 0

x = 1

That means that when x = 1, y = 0. We use this to find the value of k.

f(x) = 3x^3 - 4x + k

3*1^3 - 4(1) + k = 0

3 - 4 + k = 0

k = 1

The value of k is 1.

5 0
3 years ago
(x -1) = 26 = -4x <br> A. -7 5/7<br> B. 8<br> C. -7<br> D. -5
Volgvan
Based on the answer choices, we suspect you intend
.. (x -1) +26 = -4x

This simplifies to
.. x +25 = -4x
.. 25 = -5x . . . . . subtract x
.. -5 = x . . . . . . . divide by the coefficient of x

Selection D appears to be appropriate for the question we think you asked.
4 0
4 years ago
three notebooks and 4 binders are $9.00. two notebooks and 4 binders cost $8.00. how much does a binder cost?
Goryan [66]
$1.50 (please mark brainliest)
4 0
2 years ago
EX 6.1 How many iterations will the following for loops execute? for (int i = 0; i &lt; 20; i+ +) { } for (int i = 1; i &lt;= 20
Romashka-Z-Leto [24]

Answer:

20, 20, 15, 20, 10, and 5 iterations respectively

Step-by-step explanation:

The loop "for (int i = 0; i < 20; i+ +)" starts at i=0 and increases the counter i by 1 at the end of each iteration. The counter must be less than 20, so the values of i in the loop are 0,1,2,3,...,19. These are 20 values, and thus the code iterated 20 times.

The loop "for (int i = 0; i < 20; i+ +)" starts at i=1 and increases the counter i by 1 at the end of each iteration. The counter can't exceed 20, so the values of i in the loop are 1,2,3,4,...,20. These are 20 values, and thus the code iterated 20 times.

Similarly, in "for (int i = 5; i < 20; i+ +)" i takes the 15 values are 5,6,7,...,19. Hence, the code iterated 15 times.

The loop "for (int i = 20; i > 0; i- -)" starts at i=20 and decreases the counter i by 1 at the end of each iteration, so the values of i in the loop are 20,19,18,...,1. These are 20 values, then we have 20 iterations.

The loop "for (int i = 1; i < 20; i = i + 2)" starts at i=1 and increases the counter i by 2 at the end of each iteration. The values of i in the loop are 1,3,5,7,...,19. These are 10 values, and thus the code iterated 10 times.

The loop "for (int i = 0; i < 20; i+ +)" starts at i=1 and multiplies the counter i by 2 at the end of each iteration, so the values of i in the loop are 1,2,4,8,16. Then we have 5 iterations.

6 0
3 years ago
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