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2 years ago

X(x - 5) = -4 Solve the equation, using the quadratic formula.

Mathematics

1 answer:

leonid [27]2 years ago

5 0

1 and 4 are the answers!

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Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).

Vanyuwa [196]

$L=(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=(*)\\\\(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\\\\(b^2-c^2)^3=b^6-3b^4c^2+3b^3c^4-c^6\\\\(c^2-a^2)^3=c^6-3c^4a^2+3c^2a^4-a^6\\\\(*)=a^6-3a^4b^2+3a^2b^4-b^6+b^6-3b^4c^2+3b^2c^4-c^6+c^6-\dots\\\dots-3c^4a^2+3c^2a^4-a^6\\\\=-3a^4b^2+3a^2b^4-3b^4c^2+3b^2c^4-3c^4a^2+3c^2a^4\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)$

$R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\\\\=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\\\\=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\\\\=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\\\\L=R$

5 0

2 years ago

Read 2 more answers

I WILL GIVE BRAINLIST

puteri [66]

214.5

11x22=242
11x5/2=17.5
242-17.5=214.5

3 0

2 years ago

(-2h3n2)(-5h2n2)<br> How

IRINA_888 [86]

Answer: 9h x 8n^2

we rearrange this underneath the question (-5h-2h) (2nx3n)(2+2) or if 2^2 see explanation. It must therefore be 7h6n4

Step-by-step explanation:

if its ^2 )(power2) then the second reasonable answer is (7h-2h)(2n^2 x 2n^2)=9h x 4n^2 x4n^2 =9h 8n^2 or 17hn^2 but i leave as 9h 8n^2

You can expand only if multiplying 9hx4 for example but not combine the letters. The questions that ask you to mix are much different to this. but if you want to add them 9h+8n^2 =17hn^2

3 0

3 years ago

Please help!!!!!!!!!!!!!!

vfiekz [6]

Answer:

Step-by-step explanation:

A p - 4 is the answer to your question

8 0

3 years ago

Read 2 more answers

What is greater 16/25 or 65%

slega [8]

Hi there!

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I believe your answer is:

65% has the greater value.

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Here’s why:

We can convert both numbers into decimals and then compare the values.

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$\boxed{\text{Comparing Numbers:}}\\\\-------------\\\rightarrow\frac{16}{25}= 0.64\\\\\rightarrow 65\%=\frac{65}{100}=0.65\\ -------------\\\\\boxed{0.65 > 0.64}\\\\\text{Therefore:}\\\\\boxed{65\% > \frac{16}{25}}$

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Hope this helps you. I apologize if it’s incorrect.

6 0

2 years ago