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irinina [24]
2 years ago
9

Find the quotient. 1/4 ÷ 1/12 =

Mathematics
2 answers:
RUDIKE [14]2 years ago
6 0

Answer:

3

Step-by-step explanation:

Sadanavam1979 GREETINGS

Nady [450]2 years ago
5 0

Find the quotient. 1/4 ÷ 1/12 =

{{\rm{ \frac{1}{4}  \div  \frac{1}{12} }}} \\

{{\rm{\implies \: Divide \frac{1}{4} by \:  \frac{1}{12} \:  by \:  multiplying}}} \\ {{\rm{ \frac{1}{4} by  \: the \:  reciprocal  \: of \:  \frac{1}{12}}}}

{{\rm{ \frac{1}{4} \times 12 }}} \\

{{\rm{Multiply \:  \frac{1}{4} \:  and \:  12  \: to \:  get  \: \frac{12}{4}}}}

{{\rm{  \frac{12}{4}  }}} \\

{{\rm{Divide \:  12 \:  by \:  4  \: to \:  get  \: 3.}}}

\boxed{\begin{array}{}{{\rm\red{final \: answer:3}}}\end{array}}

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Answer:

the rocket will reach its maximum height after 4 seconds.  

Step-by-step explanation:

The first term ( -4.9(t-4)^2 ) can never be positive, so the maximum height of 80 meters is achieved when t = 4.  

5 0
2 years ago
Find the mean,median,and mode for the data.
DochEvi [55]

Mean: 116

Median: 115

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Hope this helps!

4 0
2 years ago
Read 2 more answers
If a couple were planning to have three​ children, the sample space summarizing the gender outcomes would​ be: bbb,​ bbg, bgb,​
marusya05 [52]

Answer:

(a) The sample space is: S = {bb, bg, gb, gg}

(b) The probability that the couple has two girl children is 0.25.

(c) The probability that the couple has exactly 1 boy and 1 girl child is 0.50.

Step-by-step explanation:

A boy child is denoted by, <em>b</em>.

A girl child is denoted by, <em>g</em>.

(a)

A couple has two children.

The sample space for the possible gender of the two children are:

The couple can have two boys, two girls or 1 boy and 1 girl.

So the sample space is:

S = {bb, bg, gb, gg}

(b)

It is provided that the outcomes of the sample space <em>S</em> are equally likely, i.e. each outcome has the same probability of success.

Compute the probability that the couple has two girl children as follows:

P (2 Girls) = Favorable no. of outcomes ÷ Total no. of outcomes

                =\frac{1}{4} \\=0.25

Thus, the probability that the couple has two girl children is 0.25.

(c)

Compute the probability that the couple has exactly 1 boy and 1 girl child as follows:

P (1 boy & 1 girl) = Favorable no. of outcomes ÷ Total no. of outcomes

                          =\frac{2}{4} \\=0.50

Thus, the probability that the couple has exactly 1 boy and 1 girl child is 0.50.

7 0
3 years ago
A sample of 300 urban adult residents of a particular state revealed 65 who favored increasing the highway speed limit from 55 t
forsale [732]

Answer and explanation:

Null hypothesis(H0) says sentiment for increasing speed limit in the two populations is the same

Alternative hypothesis(Ha) says sentiment for increasing speed limit in the two populations is different

Where p1 is the first population proportion =65/297= 0.22

And p2 is the second population proportion = 78/189= 0.41

P= p1+p2/n1+n2= 65+78/297+189= 0.29

Hence H0= p1-p2=0

Ha=p1-p2≠0

Test statistic= p1-p2/√p(1-p) (1/n1+1/n2)

= 0.22-0.41/√0.29(1-0.29)(1/297+1/189)

= -4.49

Critical value at 95% significance level= 1.96( from tables)

We therefore reject null hypothesis as critical value is greater than test statistic

Therefore the sentiment for increasing speed limit in the two populations is different

b. at proportions of 0.24 and 0.40 for p1 and p2 respectively

Test statistic = 0.24-0.40/0.29(1-0.29)(1/297+1/189)

= -3.78

P value is 0.0002 at 0.05 significance level

Hence probability =0.4998

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3 years ago
Find the area of the figure
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