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3 years ago

Find the quotient. 1/4 ÷ 1/12 =

Mathematics

2 answers:

RUDIKE [14]3 years ago

6 0

Answer:

Step-by-step explanation:

Sadanavam1979 GREETINGS

Nady [450]3 years ago

5 0

Find the quotient. 1/4 ÷ 1/12 =

${{\rm{ \frac{1}{4} \div \frac{1}{12} }}} \\$

${{\rm{\implies \: Divide \frac{1}{4} by \: \frac{1}{12} \: by \: multiplying}}} \\ {{\rm{ \frac{1}{4} by \: the \: reciprocal \: of \: \frac{1}{12}}}}$

${{\rm{ \frac{1}{4} \times 12 }}} \\$

${{\rm{Multiply \: \frac{1}{4} \: and \: 12 \: to \: get \: \frac{12}{4}}}}$

${{\rm{ \frac{12}{4} }}} \\$

${{\rm{Divide \: 12 \: by \: 4 \: to \: get \: 3.}}}$

$\boxed{\begin{array}{}{{\rm\red{final \: answer:3}}}\end{array}}$

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3 years ago

Which expression is equivalent to 2x - 1/3(12x - 30)?

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lisabon 2012 [21]

Answer: A. f(n) = 4 ∙ 2n-1

Step-by-step explanation:

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3 years ago

What is the probability of rolling a four then a three

spayn [35]

Answer:

$\frac{1}{36}$

Step-by-step explanation:

Total possibilities when we a roll a die at a time are 6

given we should have four for first time and then three

let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is

PROBABILITY= $\frac{\textrm{FAVOURABLE CHANCES}}{\textrm{TOTAL CHANCES}}$

Favourable chances=1

Total chances=6

Probability= $\frac{1}{6}$

the prabability to get 4 in first roll is $\frac{1}{6}$ .

let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is

Favourable chances=1

total chances=6

probability= $\frac{1}{6}$

the probability to get 3 in second roll irrespective of first one is $\frac{1}{6}$

the probability to get 4 in first time and then 3 is

The probability to occur both events at a time is multiplication of individual probabilities

So,

probablility to get 4 in first roll= $\frac{1}{6}$

probability to get 3 in second roll= $\frac{1}{6}$

probability to occur both at a same time is = $\frac{1}{6}$ $\times$ $\frac{1}{6}$ = $\frac{1}{36}$

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3 years ago