BRAINLIEST + 30PTS Use the form x^m • x^n = x^m+n to solve for (x2y)(x3y4) = x^5y^5

Mathematics

1 answer:

Dimas [21]2 years ago

7 0

Step-by-step explanation:

(x²y)(x³y⁴)
x²y×x³y⁴
x²×x³×y×y⁴
x^2+3×y^1+4
x⁵×y⁵
x⁵y⁵

You might be interested in

What is the distributive property of 8(y-7)=-16

Alex_Xolod [135]

Step-by-step explanation:

$\text{The distributive property:}\\\\a(b-c)=ab-ac\\\\8(y-7)=(8)(y)-(8)(7)=8y-56\\\\\text{If you want whole solution:}\\\\8(y-7)=-16\\8y-56=-16\qquad\text{add 56 to both sides}\\8y-56+56=-16+56\\8y=40\qquad\text{divide both sides by 8}\\\dfrac{8y}{8}=\dfrac{40}{8}\\\boxed{y=5}$

4 0

3 years ago

Read 2 more answers

I will give 5 points

ikadub [295]

Use the sum of cubes factoring rule

$a^3 + b^3 = (a+b)(a^2 - ab + b^2)$

to transform the left hand side into the right hand side.

$\frac { \sin^{3} \theta + \cos^{3} \theta } { \sin \theta + \cos \theta } = 1 - \sin \theta \cdot \cos \theta\\\\\frac { (\sin \theta + \cos \theta)(\sin^2 \theta - \sin \theta \cdot \cos\theta + \cos^2 \theta) } { \sin \theta + \cos \theta } = 1 - \sin \theta \cdot \cos \theta\\\\$

$\sin^2 \theta - \sin \theta \cdot \cos\theta + \cos^2 \theta = 1 - \sin \theta \cdot \cos \theta\\\\(\sin^2 \theta + \cos^2\theta)- \sin \theta \cdot \cos\theta = 1 - \sin \theta \cdot \cos \theta\\\\1- \sin \theta \cdot \cos\theta = 1 - \sin \theta \cdot \cos \theta \ \ \checkmark\\\\$