Write two equations to model the growth of each tree, and set the equal to each other.
Let x equal the years.
For Type A, the equation is 3x+48 because the tree grows at 3 inches per year and, it started at 4 feet (48 in).
For Type B, the equation is x+72 because the tree grows at 1 inch per year, and it started at 6 feet (72 in).
3x+48=x+72
<em>*Isolate the variable by subtracting x from each side*</em>
2x+48=72
<em>*Subtract 48 from both sides*</em>
2x=24
<em>*Divide both sides by 2*</em>
x=12 years
Hope this helps!!
.07. 07 x 10 is .7. So .07 is 1/10 of .7, and .7 is 10x as much as .07
10x^4+ 7x^3-12x^2
= x^2(10x^2+ 7x- 12)
= x^2(10x^2 -8x+ 15x -12)
= x^2[ 2x(5x-4)+ 3(5x-4)]
= x^2(5x-4)(2x+3)
x^2(5x-4)(2x+3)= 0
⇒ x= 0
or 5x-4= 0
or 2x+3= 0
⇒ x= 0
or x= 4/5
or x= -3/2
The final answer is x= 0 or x= 4/5 or x= -3/2~
Answer:
ANSWER: A) 15/40 and 28/40
Step-by-step explanation: Ive done this before lol
Answer:
Mean x¯¯¯ 2.2
Median x˜ 1
Range = 9
Q1 --> 0
Q2 --> 1
Q3 --> 3
Interquartile range: 3
Mean Absolute Deviation (MAD): 2.08
Standard deviation : 2.71
Step-by-step explanation:
1. Number of absent students:
0,1,1,0,3,2,5,1,9,0
Find the:
Mean
0, 0, 0, 1, 1, 1, 2, 3, 5, 9/10
= 22/10
= 2.2
Median
0, 0, 0, 1), 1, 1, (2, 3, 5, 9
= 1 + 1/2
= 2/2
= 1
Lower quartile
Upper quartile
Range
= 9 - 0
= 9
Interquartile range = 3
Mean absolute deviation = 2.08
Standard deviation = 2.71
