Question

-20t^5u^2v^3 ———————- 48t^7u^4v

Answer 1

Answer:

B. $\frac{-5v^2}{12t^2u^2}$

Step-by-step explanation:

Recall:

$\frac{a^x}{a^y} = a^{x -y}$

$a^{-x} = \frac{1}{a^x}$

Solution:

$\frac{-20t^5u^2v^3}{48t^7u^4v} \\ \frac{-20}{48} \cdot t^{5 -7} u^{2 -4} v^{3 -1} \\ -\frac{5}{12} \cdot t^{-2} u^{-2} v^2 \\ -\frac{5v^2}{12t^2u^2}$