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allochka39001 [22]
3 years ago
13

-20t^5u^2v^3 ———————- 48t^7u^4v

Mathematics
1 answer:
Marat540 [252]3 years ago
4 0

Answer:

B. \frac{-5v^2}{12t^2u^2}\\

Step-by-step explanation:

Recall:

\frac{a^x}{a^y} = a^{x -y}\\

a^{-x} = \frac{1}{a^x}\\

Solution:

\frac{-20t^5u^2v^3}{48t^7u^4v} \\ \frac{-20}{48} \cdot t^{5 -7} u^{2 -4} v^{3 -1} \\ -\frac{5}{12} \cdot t^{-2} u^{-2} v^2 \\ -\frac{5v^2}{12t^2u^2}

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