Answer:
the magnitude of the displacement after 5s is 137.31 m.
Explanation:
Given;
initial velocity of the projectile, u = 60 m/s
angle of projection, θ = 60°
time of motion, t = 5s
the vertical component of the velocity, 
The magnitude of the displacement after 5s is calculated as;

Therefore, the magnitude of the displacement after 5s is 137.31 m.
Answer: B) He has too many independent variables.
Explanation: Nothing in the experiment is a constant or being measured.
D - tertiary consumer
This is because it is the farther up to food chain.