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rosijanka [135]
3 years ago
15

How does mechanical weathering (from wind) of rock enhance chemical weathering (by rain) of rock

Physics
2 answers:
madreJ [45]3 years ago
7 0
The answer is letter D i believe
Colt1911 [192]3 years ago
7 0

D) Mechanical weathering exposes more surface area of the rock is the answer, i checked on USATP

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How many states in the world are there?​
aliya0001 [1]

Answer:

There are 193 member states. The UN recognises 206 states altogether.

Explanation:

8 0
3 years ago
A 25.0-meter length of platinum wire with a cross-sectional area of 3.50 × 10^−6 meter^2 has a resistance
Nookie1986 [14]
R= (rou * L) / area
where R is the wire resistance
rou: resistivity of the wire material
L : wire length
A : cross section area of wire
by sub.
0.757= (rou*25)/ 3.5*10^-6
25*rou = 2.6495*10^-6
rou= 1.0598*10^-7 ohm.m
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3 years ago
4.
Ulleksa [173]
The correct answer is C. Universal Gravitation (it was written by Issac Newton)
4 0
4 years ago
A snow ball is thrown upward at a speed of 27 m/s. How high is the snow ball 3.5 seconds later? Also, how fast is it moving at t
JulijaS [17]

Answer:

Dy = 111.66 [m]

t  = 3.5 [s]

Explanation:

To solve this problem we must use the equations of kinematics.

v_{f} = v_{o} - (g*t)\\

where:

Vf = final velocity [m/s]

Vo = initial velocity = 27 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 3.5 [s]

Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction

Vf = 27 - (9,81*3,5)

Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)

To find how high the snowball was we must use the following equation:

Dy=v_{o} *t+\frac{1}{2}*g*t

Dy = (27*3.5) + (0.5*9.81*3.5)

Dy = 94.5 + (17.16)

Dy = 111.66 [m]

5 0
3 years ago
A 0.700-kg ball is on the end of a rope that is 2.30 m in length. The ball and rope are attached to a pole and the entire appara
otez555 [7]

Answer:

The tangential speed of the ball is 11.213 m/s

Explanation:

The radius is equal:

r=2.3*sin70=2.161m (ball rotates in a circle)

If the system is in equilibrium, the tension is:

Tcos70=mg\\Tsin70=\frac{mv^{2} }{r}

Replacing:

\frac{mg}{cos70} sin70=\frac{mv^{2} }{r} \\Clearing-v:\\v=\sqrt{rgtan70}

Replacing:

v=\sqrt{2.161x^{2}*9.8*tan70 } =11.213m/s

7 0
3 years ago
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