Answer:
-25,-15,-5.5,0,15,25
Step-by-step explanation:
Given:
A plane is normal to the vector = -2i+5j+k
It contains the point (-10,7,5).
To find:
The component equation of the plane.
Solution:
The equation of plane is

Where,
is the point on the plane and
is normal vector.
Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is





Therefore, the equation of the plane is
.
Step-by-step explanation:

Answer:
(8, -5); x=8; y=-5
Step-by-step explanation:
i'll be solving via substitution
2x+3y=1; y=-2x+11
2x + 3(-2x +11) = 1
2x -6x +33 = 1
-4x = -32
x = 8
2(8) + 3y = 1
16 + 3y = 1
3y = -15
y = -5
(8, -5)
Check:
-5 = -2(8) + 11
-5 = -16 + 11
-5 = -5
Answer:
Step-by-step explanation:
a relation that is not a function