Without building the graph, find the coordinates of the points of intersection of the graph of the equation (x+2)(y+3)=0 with th
e x- and y-axes.
1 answer:
We have that
<span>(x+2)(y+3)=0
we know that
Part A)
the x-intercept is when y=0
for y=0
</span>(x+2)(0+3)=0--------> (x+2)*3=0------> 3x+6=0----> 3x=-6----> x=-2
the point is (-2,0)
Part B)
the y-intercep is when x=0
for x=0
(0+2)(y+3)=0-----> 2*(y+3)=0-----> 2y+6=0----> y=-6/2-----> y=-3
the point is (0,-3)
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(0,6)(1,3)
slope(m) = (3 - 6) / (1 - 0) = -3
y - y1 = m(x - x1)
slope(m) = -3
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