What is the index of refraction
1 answer:
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Answer:
correct option is a. 0.2 mA toward D
Explanation:
given data
B carries = 1.5 mA
C carries current = 1.3 mA
solution
we take positive direction of current going away from the point D
and negative direction of current coming towards point D
so we use here kirchoff's current law that is
iA + iB + iC = 0 ......................1
iA + 1.5 + (-1.3) = 0
iA = - 0.2 mA
so that current in wire A is 0.2 mA towards point D
correct option is a. 0.2 mA toward D
Answer:
v ≈ 4.47
Explanation:
The Formula needed = <u>KE = </u><u> m v²</u>
<u></u>
Substitute with numbers known:
2000J = × 200kg × v²
Simplify:
÷100 ÷100 (Divide by 100 on both sides)
2000J = 100 × v²
= v²
20 = v²
√ √ (Square root on both sides)
√20 = √v²
4.472135955 = v (Round to whatever the question asks)
v ≈ 4.47 (I rounded to 2 decimal places or 3 significant figures, as that is what it usually is)