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lana [24]
3 years ago
15

What is the speed of a 200-kilogram car that is driving with 2000 joules of kinetic energy? (SHOW ALL WORK)

Physics
1 answer:
Katyanochek1 [597]3 years ago
3 0

Answer:

v ≈ 4.47

Explanation:

The Formula needed = <u>KE = </u>\frac{1}{2}<u> m v²</u>

<u></u>

Substitute with numbers known:

2000J = \frac{1}{2} × 200kg × v²

Simplify:

÷100       ÷100      (Divide by 100 on both sides)

2000J = 100 × v²

\frac{2000J}{100} =  v²

20 = v²

√         √             (Square root on both sides)

√20 = √v²

4.472135955 = v (Round to whatever the question asks)

v ≈ 4.47       (I rounded to 2 decimal places or 3 significant figures, as that is what it usually is)

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The amount of force applied by individual man to balance the force at the right is 73.2 N.

<h3>Amount of force applied by individual man</h3>

The amount of force applied by individual man to balance the force at the right is calculated as follows;

F_{right} = F_{left}\\\\F_{left} = F_1 + F_2 + F_3 + F_4 + F_5\\\\F _1 = F_2 = F_3 = F_4 = F_5\\\\F_1 = \frac{F_{right}}{5} = \frac{366}{5} = 73.2 \ N

Thus, the amount of force applied by individual man to balance the force at the right is 73.2 N.

Learn more about forces here: brainly.com/question/12970081

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Answer:

C. Targets

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2 years ago
A basketball player standing up with the hoop launches the ball straight up with an initial velocity of v_o = 3.75 m/s from 2.5
denis23 [38]

Answer:

a) The maximum height the ball will achieve above the launch point is 0.2 m.

b) The minimum velocity with which the ball must be launched is 4.43 m/s or 0.174 in/ms.

Explanation:

a)

For the height reached, we use 3rd equation of motion:

2gh = Vf² - Vo²

Here,

Vo = 3.75 m/s

Vf =  0m/s, since ball stops at the highest point

g = -9.8 m/s² (negative sign for upward motion)

h = maximum height reached by ball

therefore, eqn becomes:

2(-9.8m/s²)(h) = (0 m/s)² - (3.75 m/s²)²

<u>h = 0.2 m</u>

b)

To find out the initial speed to reach the hoop at height of 3.5 m, we again use 3rd eqn. of motion with h= 3.5 m - 2.5m = 1 m (taking launch point as reference), and Vo as unknown:

2(-9.8m/s²)(1 m) = (0 m/s)² - (Vo)²

(Vo)² = 19.6 m²/s²

Vo = √19.6 m²/s²

<u>Vo = 4.43 m/s</u>

Vo = (4.43 m/s)(1 s/1000 ms)(39.37 in/1 m)

<u>Vo = 0.174 in/ms</u>

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3 years ago
Calculate the mass of an 86kg object on the moon
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If an object that is 86kg on the moon then that is the answer, 86kg.
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