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IrinaK [193]
3 years ago
9

1

Chemistry
1 answer:
larisa [96]3 years ago
3 0

Answer:

group I: alkali metals

group II (beryllium to radium): alkaline earth metals

group II (scandium to zinc , yttrium to cadmium, lanthanoid series to mercury, actinoid series to copernicium): transition metals

group VII (fluorine to astatine): halogens

group VIII: (helium to radon): noble gases

Explanation:

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C. Weak acids partially ionize
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A solution of 6.2 M H2SO4 is diluted from 2.0 L to 3.0 L. What is the molarity of the resulting solution?
makkiz [27]

Answer:

H⁣⁣⁣⁣ere's l⁣⁣⁣ink t⁣⁣⁣o t⁣⁣⁣he a⁣⁣⁣nswer:

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Explanation:

6 0
3 years ago
If 5.0 mL of a Sports Drink with an absorbance reading of 0.34 was diluted with water to 10.0 mL and was read by the colorimeter
MaRussiya [10]

Answer:

the expected absorbance of the solution = 0.17

Explanation:

From the information given:

Using Beer's Lambert Law, we have

A = ∈CL

where;

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∈ = extinction coefficient

C = concentration

L = cell length

Since Absorbance is associated with concentration.

Assuming the measurement were carried out in the same solution; Then  ∈ and L will be constant and A  ∝ C ----- (1)

Let consider the concentration to be C  (mol/L)

5.0 mL of a Sports Drink = 5.0 mL × C (mol)/1000 mL

= 5C/1000 mL

was diluted with water to 10.0 mL

So, when diluted with water to 10.0 mL; we have:

The new concentration to be : \dfrac{(5 C \times 1000) \ mol }{(1000 \times 10 \times 1000)\  mL}

Since :1000mL = 1 L

The new concentration = \dfrac{C \ mol }{2 \ L}

As stated that the initial absorbance reading A_1 = 0.34

The expected absorbance reading will be A_2 = ???

From (1)

A ∝ C

∴

\dfrac{A_2}{A_1}=\dfrac{C_2}{C}

A_2 = \dfrac{A_1}{C}

A_2 = \dfrac{0.34}{2}

A_2 = 0.17

Thus ; the expected absorbance of the solution = 0.17

8 0
3 years ago
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Answer:

Explanation:

Balanced reaction diagram is

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5 0
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AlladinOne [14]
<span>Electronegativity means the ability to attract electrons. Since He is a noble gas, it does not attract any more electrons. Cesium and Calcium are both metals, which lose electrons.
Fluorine is the right answer. It is highly electronegative which is the reason that fluorine is considered the most reactive non-metal.</span>
6 0
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