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3 years ago

Energy Reaction Diagram FOR Cellular Respiration: O2 + C6H12O6 —> CO2 + H2O

Chemistry

1 answer:

Natalka [10]3 years ago

5 0

Answer:

Explanation:

Balanced reaction diagram is

$6O_{2}+C_{6}H_{12}O_{6}$ → $6CO_{2}+6H_{2}O$

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How are the scientific method and the engineering method similar?

aliya0001 [1]

The answer is B

Explanation: Not D because only engineering does that
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3 years ago

8. Estimate the maximum volume percent of Methanol vapor that can exist at standard conditions. Vapor pressure = 88.5 mm Hg in a

sashaice [31]

Explanation:

Vapor pressure is defined as the pressure exerted by vapors or gas on the surface of a liquid.

It is known that at standard condition, vapor pressure is 760 mm Hg.

And, it is given that methanol vapor pressure in air is 88.5 mm Hg.

Hence, calculate the volume percentage as follows.

Volume percentage = $\frac{\text{given vapor pressure}}{\text{standard vapor pressure}} \times 100$

= $\frac{88.5}{760} \times 100$

= 11.65%

Thus, we can conclude that the maximum volume percent of Methanol vapor that can exist at standard conditions is 11.65%.

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3 years ago

A theory is:

SpyIntel [72]

A theory is a proposed explanation for an observation

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2 years ago

Someone anyone give me tips to finish online homework because i have 30 assignments to do

MrMuchimi

Answer:

Ok! I have four tips!

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Create A Time Table.

Gather Information For Your Online Assignments Beforehand.

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3 years ago

Which statement below matches the correct response with the proper reasoning when comparing the volatility of CH2Cl2 with CH2Br2

Nutka1998 [239]

Answer:

b. CH₂Cl₂ is more volatile than CH₂Br₂ because of the large dispersion forces in CH₂Br₂

Explanation:

CH₂Cl₂ is more volatile than CH₂Br₂ (b.p of CH₂Cl₂ = 39,6 °C; b.p of CH₂Br₂ = 96,95°C). Thus, c. and d. are FALSE

Dipole-dipole interactions in CH₂Cl₂ are greater than the dipole-dipole interactions in CH₂Br₂ because Cl is more electronegative that Br (Cl = 3,16; Br = 2,96). But this mean CH₂Cl₂ is less volatile than CH₂Br₂ but it is false.

There are large dispersion forces in CH₂Br₂ because Br has more electrons and protons than Cl. Large disperson forces mean CH₂Br₂ is less volatile than CH₂Cl₂ and it is true.

I hope it helps!

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3 years ago