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2 years ago

Could someone help me out? the sum of 9 and c

Mathematics

1 answer:

Anettt [7]2 years ago

4 0

Answer:

9+c is the sum of 9 and c

Step-by-step explanation:

hope it help you

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I need help ASAP marking brainliest

Thepotemich [5.8K]

Answer: option D -1,0,2

Step-by-step explanation:

2^x-2

When x=0

We have 2^0-2

1-2=-1

when x=1

We have 2^1-2

2-2=0

When x=2

We have 2^2-2

4-2=2

6 0

2 years ago

Read 2 more answers

A group of women tried five brands of fingernail polish and ranked them according to preference. What level of measurement is th

diamong [38]

Answer: Ordinal

Step-by-step explanation:

We know that the ordinal scale is a level of measurement which is used when we are ordering attributes according to their ranks or preferences.

For example : In an exam we arrange position of students as :

First > Second > Third and so on.

Given : A group of women tried five brands of fingernail polish and ranked them according to preference. It means she is arranging the brands in an order .

Thus this is an ordinal level of measurement .

5 0

2 years ago

Suppose you have 20 coins that total $4.00. Some coins are nickels and some are quarters. Which of the following pairs of equati

crimeas [40]

A. n+q=45n+25q=20. That should be the correct answer

5 0

2 years ago

Read 2 more answers

Must include an explanation !!<br><br> solve for x

Ira Lisetskai [31]

Answer:

x=5

Step-by-step explanation:

Volume of a rectangular prism= $\frac{1}{2}$ b x l x h

Set up you equation

120= $\frac{1}{2}$ (4 x 12 x $x$ )

Multiply inside the parentheses

120= $\frac{1}{2}$ (48x)

Multiply by $\frac{1}{2}$

120=24x

Divide by 24 on both sides

5=x

Check you answer

Volume of a rectangular prism= $\frac{1}{2}$ b x l x h

Set up your equation

$\frac{1}{2}$ (12 x 5 x 4)

Multiply inside the parentheses

$\frac{1}{2}$ (240)

Multiply by $\frac{1}{2}$

V=120yd³

8 0

2 years ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

2 years ago