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Andrej [43]
2 years ago
9

Simplify the expression (3a4)(−6a3) . Show your work and justify each step.

Mathematics
1 answer:
natali 33 [55]2 years ago
7 0

I'm going to assume the 4 and 3 are exponents and the expression is \left(3a^4\right)\left(-6a^3\right).

The first step is to separate the coefficients of 3 and -6 from the variables and to multiply those as normal:

    3 \cdot (-6) = -18

As for the variables, you want to recognize that a^4 means a \cdot a \cdot a \cdot a and a^3 means a \cdot a \cdot a, so

    a^4 \cdot a^3 = \left( a \cdot a \cdot a \cdot a\right) \cdot \left(a \cdot a \cdot a\right)

In total, there are 7 a's being multiplied, so

    a^4 \cdot a^3 = a^{4+3} = a^7

Putting this all together, we have:

    \left(3a^4\right)\left(-6a^3\right) = 18a^7

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Digiron [165]

Answer: 1211.6585 years

<u>Step-by-step explanation:</u>

The equation for exponential growth is: P=P_oe^{kt}

  • P: final population
  • P₀: initial population
  • k: rate of decay (or growth)
  • t: time

Use the half life information to find k:

\dfrac{1}{2}P_o=P_oe^{k(800)}\\\\\\\dfrac{1}{2}=e^{800k}\qquad \rightarrow \qquad \text{divided both sides by}\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=800k\qquad \rightarrow \qquad \text{applied ln to both sides}\\\\\\\dfrac{ln(\frac{1}{2})}{800}=k\qquad \rightarrow \qquad \text{divided both sides by 800}\\\\\\\large\boxed{-0.000867=k}

Next, input the information (65% decayed = 35% remaining) and the k-value to find your answer.

.35P_o=P_oe^{-0.000867t}\\\\\\.35=e^{-0.000867t}\\\\\\ln(.35)=-0.000867t\\\\\\\dfrac{ln(.35)}{-0.000867}=t\\\\\\\large\boxed{1211.6585=t}

5 0
3 years ago
What mistake did this student make?
Novay_Z [31]
X=-2 not 2.


EXPLANATION:

x-2y=12
-3x+y=-1
x-2y=12
2(-3x+y)=-1
x-2y=12
-6x+2y=-2
-5x=10
5x/-5=10/-5
x=-2
7 0
2 years ago
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Kryger [21]

Answer:

15

Step-by-step explanation:

We add the exponents so it is 10+5=15

5 0
3 years ago
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Rainbow [258]

Answer:

84mm^{2}

I think this is true

7 0
3 years ago
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