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3 years ago

13/250 or mixed number as a decimal

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

6 0

Answer:

0.052

Step-by-step explanation:

To write 13/250 as a decimal you have to divide numerator by the denominator of the fraction.

We divide now 13 by 250 what we write down as 13/250 and we get 0.052

And finally we have:

13/250 as a decimal equals 0.052

You might be interested in

Evaluate the following<br> a) 4!=<br> b) 0!=<br> c) 2! + 3!=<br> d) 3! x 4!<br> e) 10! / 7!

IRISSAK [1]

Answer:

See below for answers and explanations

Step-by-step explanation:

4! = 4*3*2*1 = 24

0! = 1

2! + 3! = 2*1 + 3*2*1 = 2 + 6 = 8

3! * 4! = 3*2*1 * 4*3*2*1 = 6 * 24 = 144

10! / 7! = 10*9*8*7*6*5*4*3*2*1 / 7*6*5*4*3*2*1 = 10*9*8 / 1 = 720

6 0

2 years ago

What is the change in y- values for every two units of x-values?

schepotkina [342]

Answer:

The graph of $y\:=\:\frac{1}{2}x$ is also attached below, which indicates that there is a change of only one unit on the y-axis for every two units of x-values.

Step-by-step explanation:

When there is a change in x values, it is basically a horizontal change. horizontal change between two values is also called the run.

And the vertically change between two values is also called the rise.

The slope is basically the ratio of the vertical (rise) and horizontal (run) changes between two points on a line.

For example, consider the equation

$y\:=\:\frac{1}{2}x$

$\mathrm{Slope\:of\:}\frac{1}{2}x:\quad m=\frac{1}{2}$

Here fore every two units of x-values, one units are moved on the y-axis.

In other words, there is a change of only one unit on the y-axis for every two units of x-values.

The graph of $y\:=\:\frac{1}{2}x$ is also attached below which is showing this.

5 0

3 years ago

LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE

Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

$\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}$

$\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}$

$\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}$

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}} }$

Use the following coordinates from the given diagram:

Point B: (x₁, y₁) = (-2, 4)

Point C: (x₂, y₂) = ( 1, 1 )

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}$

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E: (x₁, y₁) = (4, 4)

Point F: (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}$

Our calculations show that segment BC and EF have the same slope of -1. In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.

Since segments BC and EF have the same slope, then it means that $\displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}$ .

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1, 1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒ y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒ y = -x + 8.

8 0

2 years ago

I don’t know why i’m confused on this one

cestrela7 [59]

dude its going to 14cm

8 0

3 years ago

Help,anyone can help me do quetion.

3241004551 [841]

Answer:

(a) x = $128^{o}$

(b) x = $74^{o}$

Step-by-step explanation:

A. sum of angles in a polygon = (n - 2) 180

The polygon given is an irregular pentagon, where n = 5

So that;

sum of angles in a pentagon = (5 - 2) 180

= 3 x 180

= $540^{o}$

Thus,

x + 90 + 76 + 110 + 136 = $540^{o}$

x + 412 = $540^{o}$

x = $540^{o}$ - 412

x = $128^{o}$

B. The polygon given is an irregular pentagon, where n = 5.

Let the supplementary angle with angle 38 be represented by y,

y + 38 = 180

y = 180 - 38

= $142^{o}$

y = $142^{o}$

Let the supplementary angle with x be represented by z, so that;

z + 72 + 120 + 100 + 142 = $540^{o}$

z + 434 = $540^{o}$

z = $540^{o}$ - 434

= $106^{o}$

z = $106^{o}$

But, x + z = $180^{o}$

Then;

x + $106^{o}$ = $180^{o}$

x = $180^{o}$ - $106^{o}$

= $74^{o}$

x = $74^{o}$

7 0

3 years ago