Help with these three prombems please.

(2,5) and (0,1) in slope intercept form

ohaa [14]

y = 2x + 1 is the equation of line in slope intercept form

Solution:

Given that we have to write the slope intercept form

Let us first find the slope of line

The slope of line is given by formula:

$m = \frac{y_2-y_1}{x_2-x_1}$

Here the given points are (2, 5) and (0, 1)

$(x_1, y_1) = (2, 5)\\\\(x_2, y_2) = (0, 1)$

Substituting the values in formula,

$m = \frac{1-5}{0-2}\\\\m = \frac{-4}{-2}\\\\m = 2$

Thus slope of line is 2

The equation of line in slope intercept form is given as:

y = mx + c --------- eqn 1

Where, "m" is the slope and "c" is the y intercept

Substitute m = 2 and (x, y) = (0, 1) in eqn 1

1 = 2(0) + c

c = 1

Substitute c = 1 and m = 2 in eqn 1

y = 2x + 1

Thus the equation of line in slope intercept form is found

4 0

3 years ago

Uiz

kodGreya [7K]

Answer:y=-3x+14

Step-by-step explanation:

4 0

4 years ago

Graph 6x=-36 pleaseeeeeeeee helpppppp

Vedmedyk [2.9K]

Answer:

6 times 6=36

Step-by-step explanation:

HOPE THIS HELPS

3 0

3 years ago

Read 2 more answers

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the stan

torisob [31]

The point slope form of the line which passes through the points $(-5,-1)$ and $(10,-7)$ is $\fbox{\begin\\\ \math 2x+5y=-15\\\end{minispace}}$ i.e., $\fbox{\begin\\\ \bf option C\\\end{minispace}}$ .

Further explanation:

It is given that line passes through the points $(-5,-1)$ and $(10,-7)$ .

The objective is to determine the point slope form of the line which passes through the points $(-5,-1)$ and $(10,-7)$ .

The options given are as follows:

Option A: 2x-5y=-15

Option B: 2x-5y=-17

Option C: 2x+5y=-15

Option D: 2x+5y=-17

Consider the point $(-5,-1)$ as $(x_{1},y_{1})$ and $(10,-7)$ as $(x_{2},y_{2})$ .

Slope of a curve is defined as the change in the value of $y$ with respect to change in value of $x$ .

The slope of the line is calculated as follows:

$\fbox{\begin\\\ \math m=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\end{minispace}}$

To obtain the value of slope substitute the value of $x_{1},y_{1},x_{2},y_{2}$ in the above equation.

$\begin{aligned}m&=\dfrac{-7-(-1)}{10-(-5)}\\&=\dfrac{-6}{15}\\&=\dfrac{-2}{5}\end{aligned}$

Therefore, the slope of the line is $\fbox{\begin\\\ \math m=\dfrac{-2}{5}\\\end{minispace}}$

The general way to express the equation of a line in its point slope form is as follows:

$\fbox{\begin\\\ \math (y-y_{1})=m(x-x_{1})\\\end{minispace}}$

To obtain the point slope form of the equation of the line substitute the value of $m$ , $x_{1}$ and $y_{1}$ in the above equation.

$\begin{aligned}(y-(-1))&=\dfrac{-2}{5}(x-(-5))\\(y+1)&=\dfrac{-2}{5}(x+5)\\5y+5&=-2x-10\\5y+2x&=-15\end{aligned}$

From the above calculation it is concluded that the point slope form the equation of a line is $\fbox{\begin\\\ \math 5y+2x=-15\\\end{minispace}}$

Figure 1 (attached in the end) represents the graph of the function $5y+2x=-15$ .

This implies that the correct option for the point slope form of the line is option C.

Therefore, the point slope form of the line which passes through the points $(-5,-1)$ and $(10,-7)$ is $2x+5y=-15$ i.e., option C.

Learn more:

1. A problem to complete the square of quadratic function brainly.com/question/12992613

2. A problem to determine the slope intercept form of a line brainly.com/question/1473992

3. Inverse function brainly.com/question/1632445.

Answer details

Grade: High school

Subject: Mathematics

Chapter: Linear equation

Keywords: Equation, linear equation, slope, intercept, x-intercept, y-intercept, intersect, graph, curve, slope intercept form, line, y=3x/2-3, standard form, point slope form.

6 0

3 years ago

Read 2 more answers

Laura earns $225 by working 20 hours each week. Write an equation to find how much Laura earns per hour. Use h to represent the

Inessa [10]

Answer:

20h=225

Step-by-step explanation:

8 0

3 years ago