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Nataly_w [17]
2 years ago
5

2 points

Chemistry
1 answer:
Lapatulllka [165]2 years ago
6 0

Answer:

7 (7A)

Explanation:

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A piece of wood with a density of 0.85 g/cm^3 has a mass of 25 g. what is the volume of the wood?
Karolina [17]
Density = m/v  therefore    v = m/d     v = 25/0.85    v = 29.4117... cm^3 ( = 2.94 * 10^-5 m^3
5 0
3 years ago
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A student isolated 15.6 g of product from a chemical reaction. She calculated that the reactions should have produced 18.4 g of
Snezhnost [94]

Answer:

The percent yield of this reaction is 84.8 % (option A is correct)

Explanation:

Step 1: Data given

The student isolated 15.6 grams of the product = the actual yield

She calculated the reaction should have produced 18.4 grams of product = the theoretical yield = 18.4 grams

Step 2: Calculate the percent yield

Percent yield = (actual yield / theoretical yield ) * 100 %

Percent yield = (15.6 grams / 18.4 grams ) * 100 %

Percent yield  = 84.8 %

The percent yield of this reaction is 84.8 % (option A is correct)

7 0
3 years ago
Heyy pls help anyone?
madam [21]
1a. calcium chloride (CaCl2)
b. 2HCl (aq) + Ca(OH)2 (s) —> CaCl2 (aq) + 2H2O (l)

i’m not sure about the rest but i hope this helped ^^
7 0
3 years ago
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C. identify a set of four possible quantum numbers for the circled electron in manganese (mn). (there is more than one correct a
steposvetlana [31]
Although you have not provided the circled electron, I can help you with a wide explanation.

1) Atomic number of manganese is 25. That means that it has 25 protons and 25 electrons.

2) Those 25 electrons are distributed (electron configuration) as per the quantum rules:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵

3) The most reasonable is that you have been asked to give the possible quantum numbers for an electron in the 4s or 3d.

4) Those are 7 electrons and these are their possible sets of quantum numbers:
i) For the two electrons in 4s: 
n is the main energy level so n = 4
l tells the kind of orbital, which is s, so l = 0
ml is also 0 (it can be from -l to + l, so given that l i s0, ml is 0)
ms: one is +/12 and the other is -1/2 (this is the spin number).


ii) For the 5 electrons in 3d

n = 3
l can be 0, 1, or 2
if l = 0, then ml = 0

if l = 1, then ml can be -1, 0 , or 1 (from - l to + l)


ms can be either +1/2 or - 1/2 (spin)
5 0
3 years ago
In the titration of HCl with NaOH, the equivalence point is determined
kondaur [170]

Answer:

In the titration of HCl with NaOH, the equivalence point is determined from the point where the phenolphthalein turns pink and then remains pink on swirling.

Explanation:

The equivalence point is the point at which exactly enough titrant (NaOH) has been added to react with all of the analyte (HCl). Up to the equivalence point, the solution will be acidic because excess HCl remains in the flask.

Phenolphtalein is chosen because it changes color in a pH range between 8.3 – 10. Phenolphthalein is naturally colorless but turns pink in alkaline solutions. It remains colorless throughout the range of acidic pH levels, but it begins to turn pink at a pH level of 8.3 and continues to a bright purple in stronger alkalines.

It will appear pink in basic solutions and clear in acidic solutions.

The more NaOH added, the more pink it will be. (Until pH≈ 10)

In strongly basic solutions, phenolphthalein is converted to its In(OH)3− form, and its pink color undergoes a rather slow fading reaction and becomes completely colorless above 13.0 pH

a. from the point where the pink phenolphthalein turns colorless and then remains colorless on swirling.

⇒ the more colorless it turns, the more acid the solution. (More HCl than NaOH)

b. from the point where the phenolphthalein turns pink and then remains pink on swirling.

The equivalence point is the point where phenolphtalein turns pink and remains pink ( Between ph 8.3 and 10). (

Although, when there is hydrogen ions are in excess, the solution remains colorless. This begins slowely after ph= 10 and can be noticed around ph = 12-13

c. from the point where the pink phenolphthalein first turns colorless and then the pink reappears on swirling.

Phenolphthalein is colorless in acid solutions (HCl), and will only turn pink when adding a base like NaOH

d. from the point where the colorless phenolphthalein first turns pink and then disappears on swirling

Phenolphthalein is colorless in acid or neutral solutions. Once adding NaOH, the solution will turn pink. The point where the solution turns pink, and stays pink after swirling is called the equivalence point. When the pink color disappears on swirling, it means it's close to the equivalence point but not yet.

3 0
2 years ago
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