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3 years ago

Help? how can i do this?

Chemistry

1 answer:

lubasha [3.4K]3 years ago

7 0

882µg x 1g/10^6µg = 8.82 x 10^-4 g

use the conversion factor 1µg = 10^-6m

8.82 x 10^-4g

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What evidence indicates that nitric acid (HNO3) is a strong acid?

GREYUIT [131]

Answer:

The presence of hydrogen ions

Explanation:

Nitric acid is formed when hydrogen ions combine with nitrogen oxide ions leading to formation of a strong acid. Wheareas for strong bases the hydroxyl iins must be present, for strong acid, the hydrogen ions contribute to the acidity. Therefore, from the formula of nitric acid, it has hydrogen ions, an indicator of a strong acid.

8 0

3 years ago

Find percent yield:

saveliy_v [14]

Answer: The percent yield of the reaction is 91.8 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For $B_5H_9$ :

Given mass of $B_5H_9$ = 4.0 g

Molar mass of $B_5H_9$ = 63.12 g/mol

Putting values in equation 1, we get:

$\text{Moles of }B_5H_9=\frac{4g}{63.12g/mol}=0.0634mol$

For oxygen gas:

Given mass of oxygen gas = 10.0 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{10g}{32g/mol}=0.3125mol$

The chemical equation for the reaction of $B_5H_9$ and oxygen gas follows:

$2B_5H_9+12O_2\rightarrow 5B_2O_3+9H_2O$

By Stoichiometry of the reaction:

12 moles of oxygen gas reacts with 2 moles of $B_2H_5$

So, 0.3125 moles of oxygen gas will react with = $\frac{2}{12}\times 0.3125=0.052mol$ of $B_2H_5$

As, given amount of $B_2H_5$ is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

12 moles of oxygen gas produces 5 moles of $B_2O_3$

So, 0.3125 moles of oxygen gas will produce = $\frac{5}{12}\times 0.3125=0.130moles$ of water

Now, calculating the mass of $B_2O_3$ from equation 1, we get:

Molar mass of $B_2O_3$ = 69.93 g/mol

Moles of $B_2O_3$ = 0.130 moles

Putting values in equation 1, we get:

$0.130mol=\frac{\text{Mass of }B_2O_3}{69.63g/mol}\\\\\text{Mass of }B_2O_3=(0.130mol\times 69.63g/mol)=9.052g$

To calculate the percentage yield of $B_2O_3$ , we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of $B_2O_3$ = 8.32 g

Theoretical yield of $B_2O_3$ = 9.052 g

Putting values in above equation, we get:

$\%\text{ yield of }B_2O_3=\frac{8.32g}{9.052g}\times 100\\\\\% \text{yield of }B_2O_3=91.8\%$

Hence, the percent yield of the reaction is 91.8 %

6 0

4 years ago

If 7.84 x 10^7 J of energy is released from a fusion reaction, what amount of mass in kilograms would be lost? Recall that c = 3

docker41 [41]

Use the formula
E=mc^2

plug the values,

The amount of mass in kilograms would be lost is 8.71 x 10^-10

7 0

3 years ago

Read 2 more answers

The purpose of technology is to solve problems and meet needs. TrueFalse

galina1969 [7]

Answer:

True

Explanation:

Technology has been mans best friend for a while due to the fact that they can make things to help others and create more jobs and help everyone overall.

7 0

3 years ago

Read 2 more answers

A chemical reaction occurs when blank

PIT_PIT [208]

Answer:

When atoms are formed or broken.

Explanation:

The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products.

8 0

3 years ago

Help? how can i do this?​

Help? how can i do this?