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2 years ago

Evaluate −x+| y | when x=1/3 and y=−7/4. Write your answer as a fraction in simplest form.

Mathematics

1 answer:

Mama L [17]2 years ago

5 0

Answer: = $\frac{17}{12}\quad \left(\mathrm{Decimal:\quad }\:1.41666\dots \right)$

Step-by-step explanation:

$-\frac{1}{3}+\left|-\frac{7}{4}\right|$

$=-\frac{1}{3}+\frac{7}{4}$

$=\frac{17}{12}$

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Use the zero product property to find the solutions to the equation 2x2 + x - 1 = 2

Firdavs [7]

Answer:

Step-by-step explanation:

Given

2x² + x - 1 = 2 ( subtract 2 from both sides )

2x² + x - 3 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 2 × - 3 = - 6 and sum = + 1

The factors are - 2 and + 3

Use these factors to split the x- term

2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(2x + 3) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - $\frac{3}{2}$

8 0

2 years ago

The body temperatures of adults have a mean of 98.6°F and a standard deviation of 0.60° F. Describe the center and variability o

amid [387]

Answer:

center = 98.6, variability = 0.08

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

The center is the mean.

So $\mu = 98.6$

The standard deviation of the sample of 50 adults is the variability, so

$s = \frac{0.6}{\sqrt{50}} = 0.08$

So the correct answer is:

center = 98.6, variability = 0.08

7 0

3 years ago

Which statement and reason accurately completes the proof? 3. ∠BDE ≅ ∠BAC; Corresponding Angles Postulate 5. ΔBDE ~ ΔBAC; Angle-

ElenaW [278]

Answer:

3. ∠BDE ≅ ∠BAC; Corresponding Angles Postulate 5. ΔBDE ~ ΔBAC; Angle-Angle (AA) Similarity Postulate

Step-by-step explanation:

3) Statement ∠BDE ≅ ∠BAC;

Corresponding Angles Postulate

The Corresponding Angles Postulate states that given two parallel lines, in this case DE and AC cut by a transversal one (AB) than these corresponding angles are congruent.

5) ΔBDE ~ ΔBAC; Angle-Angle (AA) Similarity Postulate

If two pairs of corresponding angles are congruent (∠D and ∠A, ∠E and ∠C) than these triangles are similar.