since LM=LN there values are same which is given as 5.5 cm and MN =7cm
now draw a line LM which is 5.5 cm long. From one point of this line construct an arc 5.5 cm in upward direction.Then from the opposite end of the same line LM construct an arc 7 cm long in upward direction. Let it meet the the first arc at any point. The arcs will meet for sure at any angle. Join the two ends of line LN to this point where they meet. We get a triangle!
Remember to mark LM , LN and MN as soon as u draw them so as to avoid confusion.
<em>IF U WANT I'LL DO IT AND SEND A PHOTO</em>
A) $7. 69 change she will get back when she use 50.00 for her pants and sweater
Answer:
i cant read it
Step-by-step explanation:
maby inhance the image
Supplementary angles because because angle 1 + angle 2 = 180° so they form a line
The ratio of the area of ∆ABC to the area of ∆DEF is; 1:100.
<h3>What is the ratio of the area of ∆ABC to the area of ∆DEF?</h3>
Since, a major criterion for similarity and congruence of triangles is that the ratio of corresponding sides are equal.
On this note, since the task content suggest that the ratio of the perimeters is; 1:10, it follows from conventional mathematics that the ratio of their areas is given as; 1²:10²; 1:100.
Read more on congruent triangles;
brainly.com/question/9217675
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