Does limit exist at removable discontinuity

If the scale factor between a scale drawing of a rectangle and the real object is 1:3 what would be the ratio of the areas?

Ivanshal [37]

Answer:

The ratio of the areas will be will be 1 : 9

Step-by-step explanation:

The linear scale factor represents a ratio that is used to multiply the dimensions of objects so that accurate geometries can be transferred between real-life and paper.

The linear scale factor is quite different from the area scale factor but related to it in the following way:

The area factor can be obtained by squaring the linear scale factor.

This is Area factor = (Linear scale factor) ^2.

Linear scale factor = (1:3)

Area factor = $1^2 : 3^2$

Area factor will be 1: 9

Thus, when the linear scale factor is 1:3 the area factor will be 1 : 9

7 0

3 years ago

(5/6)^4x=(36/25)^9-x, please help solve for x, and the 9-x is all superscript

stiks02 [169]

$\frac{36}{25}=\frac{6^2}{5^2}=\left(\frac{6}{5}\right)^2=\left(\frac{5}{6}\right)^{-2}\\\\therefore:\\\\\left(\frac{5}{6}\right)^{4x}=\left[\left(\frac{5}{6}\right)^{-2}\right]^{9-x}\\\\\left(\frac{5}{6}\right)^{4x}=\left(\frac{5}{6}\right)^{-2(9-x)}\iff4x=-2(9-x)\\\\4x=-2\cdot9-2\cdot(-x)\\\\4x=-18+2x\ \ \ \ \ |subtract\ 2x\ from\ both\ sides\\\\2x=-18\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{x=-9}$

$Use:\\a^{-n}=\left(\frac{1}{a}\right)^n\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\\left(\frac{a}{b} \right)^n=\frac{a^n}{b^n}$

6 0

3 years ago

Read 2 more answers

The violent-crime rate in a certain state of the country in that year was 1,496. Would this be an outlier? O A. No, because it i

Kobotan [32]

Answer:

The violent-crime rate in a certain state of the country in that year was 1,496

Would this be an outlier?

C. Yes, because it is greater than the upper fence.

(d) Do you believe that the distribution of violent-crime rates is skewed or symmetric?

C. The distribution of violent-crime rates is skewed right.

Step-by-step explanation:

The violent-crime rate in a certain state of the country in that year was 1,496

The lower fence is 272.8 - 1.5 x 255.5 = -110.45 crimes per 100,000 population.

The upper fence is 528.3 + 1.5 x 255.5 = 911.55 crimes per 100,000 population.

Since violent-crime rate in this certain state of the country in that year is greater than the upper fence (1496>911.55), then it is an outlier.

(d) Do you believe that the distribution of violent-crime rates is skewed or symmetric?

The distribution of violent-crime rates is not symmetric, as there are extreme values in the tail, which tend to pull the mean in the direction of the tail to have data are either skewed left or skewed right, in this case it is skewed right, as there are large observations in the right tail that tend to increase the value of the mean, while having little effect on the median.

8 0

3 years ago

From least to greatest 3/5, 7/8, 1/5

RUDIKE [14]

1/5, 3/5, 7/8 is from least to greatest.

5 0

3 years ago

Read 2 more answers

Help! Find x in the given figure.<br><br><br><br> x = inches.

aleksandr82 [10.1K]

There are a few relations related to tangents and secants that you are expected to remember. These problems make use of those.

1. When chords cut each other, the product of the segment lengths of one of them is equal to the product of the segment lengths of the other. Here, one of the chords is a diameter. That is special in that it is the bisector of any chord it crosses at right angles. That means ...
x·x = 2·6
x = √12 = 2√3

2. Secants from an external point have the same product of measures to the near and far intersection points with the circle. Since there is only one intersection point with a tangent, the near and far lengths are the same.
4·(4+8) = x·x
x = √48 = 4√3

6 0

4 years ago