Answer:
c. x21 + x22 + x23 less or equal than 2800 y2
Step-by-step explanation:
The plant has a maximum capacity of 2800 then the sum of all these operations must be equal to or less than 2800. The site of the plant has capacity constraint which needs to be determine through equation. The total capacity for the plant 2 is only 2800 the operation has to be distributed with keeping in mind the capacity limit.
5*5*5=125
5²*5=125
5√5 is your answer
Answer:
Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .
Step-by-step explanation:
We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;
Mean,
= 1.3 cm and Standard deviation,
= 0.01 cm
Also, since distribution is normal;
Z =
~ N(0,1)
Let X = range of diameters
So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)
P(X < 1.33) = P(
<
) = P(Z < 3) = 0.99865
P(X <= 1.27) = P(
<
) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865
= 0.00135
P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .
Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .
Answer:
16(4b - c)
Explanation:
16 x 4b = 64b
16 x c = 16c
Answer:
c.20
Step-by-step explanation:
first step:24÷3=8
final step: 12+8=20