The only that has the shape of the one below.
y = -4(x^3 + 7x^2+8x - 16)
Let x = 1
y = - 4(1 + 7 + 8 - 16)
y = 0
y = -4(x -1)(x^2 + 8x + 16)
y = -4(x - 1)(x + 4)^2
Answer:
11
Step-by-step explanation:
1.80m + 0.6s = 12.00
[substitute the value of m into the equation]
1.80×(3) + 0.6s = 12
5.4 + 0.6s = 12
[make s the subject of the formula]
0.6s = 12 - 5.4
0.6s = 6.6
[divide both sides of the equation by 0.6]
0.6s / 0.6 = 6.6 / 0.6
s = 11
To prove that 11 is correct
[substitute the value of m and s into the equation]
1.80m + 0.6m = 12.00
1.80×(3) + 0.6×(11) = 12.00
5.4 + 6.6 = 12.00
12.00 = 12.00
The 38th term in the sequence is -51
Answer:
11.2 units
Step-by-step explanation:
From (-7, -7) to (-2, 3) is 5 units horizontally and 10 units vertically. Thus we have a right triangle with sides 5 and 10 respectively. The length of the hypotenuse of this triangle is the distance between (-2, 3) & (-7, -7):
d = √(5² + 10²) = √(25 + 100) = √125 = √25√5, or 5√5.
This is approximately 11.2 units
a. The difference between two outputs that are 1 unit apart.
You need to Use y2 - y1 / x2 - x1 to find the difference
I will choose x2 as 1 and x1 as 0
(29 - 21) / (1 - 0)
8/1 so The difference is 8 per 1 unit.
b. Use the same formula
I will choose -3 as x2 and -5 as x1
(5 - (-11)) / (-3 - (-5))
(5 + 11) / (-3 + 5)
16 / 2 so the difference is 16 per 2 units.
c. I will choose 2 as x2 and -1 as x1
(45 - 21) / (2 - (-1))
24/3 so the difference is 24 per 3 units.
d. The ratios of the differences to the input intervals reduced all equal each-other, which is 8 per 1 unit.
