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GalinKa [24]
2 years ago
14

A woman store sells the following categories of clothing for the following prices Blouse :¢14 each, skirt:¢16 each, Dress :¢25 e

ach, panty hose:2pairs for 3¢ each and socks:¢17. A lady goes to the store on a day when the store has 20% off sale on all skirts. If yaa buys 2skirts, 1 dress, and 4 pairs of panty hose, how much money does the lady have to pay
​
Mathematics
1 answer:
eimsori [14]2 years ago
3 0
Hello! What currency is this question in?
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List the 6 congruency statements given triangle KNC is congruent to triangle GJ A. angle K is congruent to angle C; angle N is c
Ivanshal [37]
The answer to your question is C
4 0
3 years ago
The value of a new truck decreases exponentially at a rate of 4.8% per year. If the purchase price of the new cars $42,000, how
Usimov [2.4K]

The worth of the car after it is paid off 5 years later given the rate of exponential depreciation is $32,842.34.

<h3>What is the worth of the car?</h3>

When the car declines in value, it means that the car is depreciating. The formula that can be used to determine the value of the car with the depreciationn rate is:

FV = P (1 - r)^n

  • FV = Future value
  • P = Present value
  • R = rate of decline
  • N = number of years

$42,000 x (1 - 0.048)^5 = $32,842.34

To learn more about future value, please check: brainly.com/question/18760477

7 0
2 years ago
Lieutenant James made an average of 3 arrests per week for 4 weeks. How many arrests does she need to make in the fifth week to
tankabanditka [31]

Answer:

5

Step-by-step explanation:

We want the average arrests to be 4. It can be done by calculating the average between the average arrests and arrests during the 5th week, so we get:

Avg(1,2,3,4,5) = (Avg(1,2,3,4) + A(5)) / 2

Where Avg(x) is the average of arrests in given weeks, and A(x) is the number of arrests in a given week.

Solving for A(5) => A(5) = 2*Avg(1,2,3,4,5) - Avg(1,2,3,4) = 2 * 4 - 3 = 8-3 = 5

3 0
3 years ago
ANSWER ALL 5 PARTS.
N76 [4]
A function f from a set A to a set B is defined as a relation that assings to each element  x in the set A exactly one element y in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is x feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let x be the width of the tomato patch, then the function that matches this statement is:

\boxed{Wa(x)=\frac{x}{2}}

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

</span>\boxed{La(x)=x+2}
<span>
2. Ar</span>ea of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:

</span>A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}
<span>
3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
<span>
4. W</span>rite the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:<span>

</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

</span>31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06
<span>
Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

6 0
3 years ago
2100 divided by 55 (show your work) I hate math
leonid [27]

Answer:

1155

Step-by-step explanation:

We need to determine 55% of 2100 now and the procedure explaining it as such

Step 1: In the given case Output Value is 2100.

Step 2: Let us consider the unknown value as x.

Step 3: Consider the output value of 2100 = 100%.

Step 4: In the Same way, x = 55%.

Step 5: On dividing the pair of simple equations we got the equation as under

2100 = 100% (1).

x = 55% (2).

(2100%)/(x%) = 100/55

Step 6: Reciprocal of both the sides results in the following equation

x%/2100% = 55/100

Step 7: Simplifying the above obtained equation further will tell what is 55% of 2100

x = 1155%

Therefore, 55% of 2100 is 1155

6 0
2 years ago
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