The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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They lost L games.
They won W games.
W = 2L
W + L = 96, but W = 2L, so
2L + L = 96
3L = 96
L = 32
W = 2L = 2 * 32 = 64
They won 64 games.
Answer:
Step-by-step explanation:
56.27 =
50
+ 6
+ 0.2
+ 0.07
Expanded Factors Form:
56.27 =
5 × 10
+ 6 × 1
+ 2 × 0.1
+ 7 × 0.01
Expanded Exponential Form:
56.27 =
5 × 101
+ 6 × 100
+ 2 × 10-1
+ 7 × 10-2
Word Form:
56.27 =
fifty-six and twenty-seven hundredths
Answer:
120 000 m^2
Step-by-step explanation:
I ASSUME you're being asked to convert from km^2 to m^2.
For this you need to identify the conversion rate, which is 1 000 000 m^2 / 1 km ^2. Multiply by the thing you're converting from and cancel the units.
(1 000 000 m^2 / 1 km ^2) x 0,12 km^2 = 120 000 m^2 (the km^2 cancels out, leaving you only with your target unit of m^2)
Answer:
B-16
Step-by-step explanation:
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