All categories

3 years ago

Math algebra 2 show you’re work plz

Mathematics

1 answer:

LenKa [72]3 years ago

5 0

9514 1404 393

Answer:

(t, u, w) = (1, -2, -2)

Step-by-step explanation:

A graphing calculator makes short work of this, giving the solution as ...

(t, u, w) = (1, -2, -2)

There are many ways to solve this "by hand." Here's one of them.

Add the first and third equations. Their sum is ...

-3t +4w = -11 . . . . . [eq4]

Add this to twice the second equation. That sum is ...

(-3t +4w) +2(-4t -2w) = (-11) +2(0)

-11t = -11

t = 1

Substituting this into the second equation gives ...

-4(1) -2w = 0

w +2 = 0 . . . . divide by -2

w = -2 . . . . add -2

Substituting for t in the third equation lets us find u.

2(1) -2u = 6

-1 +u = -3 . . . . . divide by -2

u = -2 . . . . add 1

The solution is (t, u, w) = (1, -2, -2).

You might be interested in

Suppose that 70% of the orders on a particular website are shipped to the person who is making the order and the remaining 30% a

Lera25 [3.4K]

Answer:

0.18 ; 0.1875 ; No

Step-by-step explanation:

Let:

Person making the order = P

Other person = O

Gift wrapping = w

P(p) = 0.7 ; P(O) = 0.3 ; p(w|O) = 0.60 ; P(w|P) = 0.10

What is the probability that a randomly selected order will be a gift wrapped and sent to a person other than the person making the order?

Using the relation :

P(W|O) = P(WnO) / P(O)

P(WnO) = P(W|O) * P(O)

P(WnO) = 0.60 * 0.3 = 0.18

b. What is the probability that a randomly selected order will be gift wrapped?

P(W) = P(W|O) * P(O) + P(W|P) * P(P)

P(W) = (0.60 * 0.3) + (0.1 * 0.7)

P(W) = 0.18 + 0.07

P(W) = 0.1875

c. Is gift wrapping independent of the destination of the gifts? Justify your response statistically

No.

For independent events the occurrence of A does not impact the occurrence if the other.

4 0

2 years ago

pablo is making a sandwich for a picnic.He has 32 slices of turkey and 24 slices of cheese.If pablo wants to make the maximum nu

mezya [45]

You find the HCF which is 8
you divide 32 and 24 by 8
which will give you 4 and 3 respectively
therefore there will be 4 slices of turkey and 3 slices of cheese in each sandwich.
and there will be 8 sandwiches...

6 0

3 years ago

Work out the volume of this sphere.

Ratling [72]

Step-by-step explanation:

Find the radius: 19 ÷ 2 = 9.5

4/3 x 22/7 x 9.5 x 9.5 x 9.5 = 3592

3592/3 =

1197.3 (Rounded to 1 decimal place)

Answer: 1197.3cm3

(I have never done area or perimeter of sphere before, but I did for other shapes. This is just my attempt using the methods I did for other shapes by the way)

3 0

2 years ago

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago

Here is the histogram of a data distribution. All class widths are 1.

stich3 [128]

The median of the data is 5 if the all class widths are 1, option (C) is correct.

<h3>What is the median?</h3>

A median is a middle number in a series of numbers that have been arranged to lift, and it might be more informative of the set of data than the average. When there are extremes in the sequences that might affect the average of the numbers, the median is sometimes employed instead of the mean.

In the histogram, 15 data values are given:

1, 2, 2, 3, 3, 3, 4, 5, 6, 6, 7, 7, 7, 8, 9

The mid-value is 5 which is on the 8th place

Thus, the median of the data is 5 if the all class widths are 1, option (C) is correct.

Learn more about the median here:

brainly.com/question/21396105

#SPJ1

8 0

2 years ago