1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleonysh [2.5K]
3 years ago
15

The unit used to measure the diameter of an atom is an?

Chemistry
2 answers:
ohaa [14]3 years ago
6 0

Answer:

Atomic Radii

Have a great day!

iren [92.7K]3 years ago
4 0
Atomic Radii
Measured in terms of angstroms (Å)
You might be interested in
A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a
Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = m C .ΔT

m is mass of the solution = 151.8 mL * \frac{1 g}{1 mL} = 151.8 g

C is the specific heat of solution = 4.18 \frac{J}{g. ^{0}C}

ΔT is the temperature change = 31.50^{0}C - 21.45^{0}C = 10.05^{0}C

q = 151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J

Moles of NaOH = 101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol NaOH

Moles of H_{2}SO_{4} = 50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}

Enthalpy of the reaction = \frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol

5 0
3 years ago
Which is not a descriptor or tactic used by abusers?
attashe74 [19]
It should be B. All of the other choices are used often by abusers
4 0
3 years ago
I need information about <br>"forming colloid"<br>THANK YOU! ​
notka56 [123]

Answer:

Condensation methods from colloidal particles by aggregation of molecules or ions. Examples of colloids are really in common in evryday life, eg. Mayonnaise, butter, milk, gelatin, paper etc..

Every colloid consists of two parts :colloidal particles and the dispersing medium.

3 0
3 years ago
(10 points) easy WILL GIVE BRAINLIEST
nignag [31]

Answer:

Both b/c a chemical formula tells you how many and a sketch formula shows how they are bonded together.

Molecular formulas show how many atoms of each element one molecule of a compound contains. Note: Ionic compounds are generally crystalline solids with high melting points. Other compounds, however, have very different properties.

4 0
2 years ago
Read 2 more answers
Why doesn't glass exhibit crystalline form
ser-zykov [4K]
It doesn't have a 3 dimensional pattern
7 0
3 years ago
Other questions:
  • Which substance is a primary source of hydrocarbons? A. cotton B. metals C. petroleum D. soil
    9·2 answers
  • Which term represents the attraction one atom has for the electrons in a bond with another atom? A. electronegativity B. electri
    13·1 answer
  • 1.* Write the name and symbol of the ion formed when
    8·2 answers
  • 4.65 L of nitrogen at standard pressure is compressed into a 0.480 L container. What is the new pressure in kPa?
    12·1 answer
  • The complete combustion (reaction with oxygen) of liquid octane (c8h18) a component typical of the hydrocarbons in gasoline, pro
    9·1 answer
  • NEED HELP ASAP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    14·2 answers
  • Which is greater , 3 moles of sulfur or 2 moles of iron sulphide
    9·2 answers
  • Calculate the activation energy for vacancy formation in Al given that the equilibrium number of vacancies at a temperature of 7
    15·1 answer
  • Silver has a density of 10.5 g/cm³, and gold has a density of 19.3 g/cm³. Which would have a greater mass, 5 cm³ of silver or 5
    13·1 answer
  • Which of these mixtures could be most easily seperate by filtaration?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!