A student titrates an unknown amount of potassium hydrogen phthalate (KHC8H4O4, abbreviated as KHP) with 21.30 mL of a 0.1161 M

Question

svp [43]

3 years ago

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A student titrates an unknown amount of potassium hydrogen phthalate (KHC8H4O4, abbreviated as KHP) with 21.30 mL of a 0.1161 M

NaOH solution. KHP (molar mass

Chemistry

1 answer:

schepotkina [342] · Answer 1 · 2022-03-20T13:55:17+03:00

Answer:

0.5050g of KHP were titrated

Explanation:

<em>... (molar mass = 204.22 g/mol) has one acidic hydrogen. What mass of KHP was titrated (reacted completely) by the sodium hydroxide solution?</em>

<em />

The KHP is a salt used as standard to determine concentrations of bases as NaOH solutions. The reaction that occurs is:

KHP + NaOH → KP⁻Na⁺ + H₂O

<em>Only 1 hydrogen is acidic. Only 1 hydrogen reacts with NaOH</em>

In the reaction you can see that 1 mole of NaOH reacts per mole of KHP

To find mass of KHP we need to determine its moles finding moles of NaOH (The moles of KHP required to reach endpoint = Moles of NaOH added):

<em>Moles NaOH:</em>

21.30mL = 0.02130L * (0.1161mol / L) = 0.002473 moles of NaOH = Moles KPH

With mass of KHP and its molar mass we can solve the mass of KHP:

0.002473 moles of KHP * (204.22g/mol) =

<h3>0.5050g of KHP were titrated</h3>